How to find quantity of cement mortar?
I want to know the req quantity of cement for plastering 300
sft in final coat with 12 mm. Any math involved? Plz help
Answers were Sorted based on User's Feedback
Answer / mukul chand
300 sft = 300*0.0924=27.72 sqm
Therefor wet vol. of mortar = 27.72 * 0.012 = 0.33264 cum
Increased by 20% for filling the depression etc.
= 0.33264 + 1/5 0.33264 = 0.4 cum (wet)
= 0.4 + 1/3 0.4 = 0.533 cum (dry)
Summation of proportion = 6+1 = 7 (1:6)
Therefor cement require = 0.533/7 = 0.761 cum.
Or 0.761 * 1440 = 109.71 kg.
| Is This Answer Correct ? | 34 Yes | 5 No |
Answer / sateesh patil kris cooper pmc
Your Area is=27.87 Sqmt
Thickness is=0.012m
Total=27.87X0.012=0.33 Cum
25% of Dry Mix=25/100X0.33=0.0825 Cum
30% of Wet mix is=30/100X0.33=0.099 Cum
Total=0.33+0.0825+0.099=0.5115 Cum
If your Mix proption is 1:4 then you do
0.5115/(1+4)=0.1023
1 Part of cement is 0.1023X1=0.1023 Cum/0.035 Cum=2.92 Bags
Sand is 0.1023X4=0.4092 Cum=14.43 Cft
| Is This Answer Correct ? | 24 Yes | 4 No |
Answer / indhumathi
cement required=96.192
it depends on the mix ratio.i give the quantity for c.m 1:5
area to be plastered=27.87sq.m(300 sq ft)
thickness of coat=12mm
volume of mortar required=27.87*.012=.334m3
sand required for .334m3=.0334m3
cement required=(weight of cement in 1m3/mix ratio)*total
volume
=(1440/5)*.334=96.192kg
| Is This Answer Correct ? | 49 Yes | 31 No |
Answer / sachin sharma
Total Volume =(300/10.76)*.012=0.334cum
Increase 55% for dryness factor and unevenness
=1.55 * .334
=0.52CUM
Consider mix 1:6
Cement Content=(0.52/7)*28.8
=2.14 Bags
| Is This Answer Correct ? | 13 Yes | 4 No |
Answer / rafeek shehu ibrahim
Mixing ratio 1:5 12mm thickness
Add 25% for Unevenness volume of wet mortar
Add 30% for Dry mix Volume
so, 55% is to be added
=300/10.76*0.012
=0.334m3 wet mortar need for 300ft2/27.88m2(12mm thick)
so,Dry volume=0.334+0.334*55%
=0.517m3
red Cement=(volume of Dry material/summation of proportion)
----------------------------------------------
Volume of 1bag Cement
=(0.517/6)
--------
0.035(volume of 1 Bag of cement)
Answer =2.46Bags
| Is This Answer Correct ? | 10 Yes | 1 No |
Answer / sjtbehera
ans- you told 300sqft and 12mm th. Ratio is 1:6
convert 300 sqft = 27.77 sqm
= .012x 27.77= .333cum
= .333+1/5x .333 = .399 this is done for 20%
increase in volume mortar for joints depression and wastage
= .399+1/3 x .399 = .532 cum this done when mortar
increase 1/3ed volume when dry.
Than calculating cement = .532/7 = .076 cum = 2.1 bags
where as 1 bag= .0347 cum
7 is the summation of 1:6 ratio
sand - .076 x 6 = .456 cum
| Is This Answer Correct ? | 17 Yes | 10 No |
Answer / er.puspk kumar sahu
area of plastering=300sq.ft=300/10.76=27.88sq.mt
thickness of plaster=12mm=0.012m
ratio of mortar=(1:6)summation of ratio=7
total volume of cement plastering=(27.88x0.012)cum
=0.334cum
0.334+55%=0.517cum(extra 55% for dry material )
cement=0.517/7=0.073cum
0.073/0.035=2.08bags(1 cum cement volume perbag=0.035cum)
sand=0.517/6=0.086cum=3.07
| Is This Answer Correct ? | 9 Yes | 3 No |
Answer / mohammed aijaz hussain
Volume of Wet Mortar = 12 mm X 300 cc.ft.
= 12/1000 X 300/10.76
= 0.335 cu.m.
Add 20% for depressions, joints and wastage:
= 0.067+0.335
= 0.402 cu.m.
Volume of Dry Mortar = 1.3 X 0.402
= 0.523 cu.m. = 18.45 cu.ft.
| Is This Answer Correct ? | 7 Yes | 1 No |
Answer / k pramod
wet mixed mortar for uniform layer =1.2cu. m
adding 30% to fill up joints,uneven surfaces,etc.,the
quantity becomes to 1.2+.36=1.56.
increasing by 25% the total dry volume =1.95cu m== 2.00cum
For, 1:6 cement sand ratio =2/(1+6)=.3
sand =.30*6=1.8cu m ,say =2.0cu m...
no of cement bags requiered are=9
| Is This Answer Correct ? | 21 Yes | 16 No |
Answer / muhammad farid
If ratio of plaster is 1:5 & thickness is 12mm
Dry material is 300/10.76x0.012=0.334cm
Wet material for plaster 1.30x0.334=0.434cm
Cement req. 0.434/6x35.31=2.55 cft or 102.16kg or
2.04Bags of 50kg
| Is This Answer Correct ? | 6 Yes | 1 No |
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