Answer / imran ali

1.54 is right

Answer / tarique08

suppose, concrete mix ratio = 1:1.5:3
then, sum = 1 1.5 3 = 5.5

as we know,dry material required for 1 cum. of concrete =
1.54 cum.
then we can find -:

(1) cement = 1*1.54/5.5 = .28 cum. or .28cum.* 28.8= 8.06
bags.

(2) sand = 1.5* 1.54/5.5 = .42 cum.
or .42cum.* 35.3 = 14.83 cubic feet.

(3) coarse aggregate = 3* 1.54/5.5 = .84 cum.
or .84 cum.* 35.3 = 29.65 cubic feet.

so, dry ingredient quantity required for 1 m3 of concrete-:

cement = 8.06 bags.
sand = 14.83 cft.
coarse aggregate = 29.65 cft.

Answer / waqas ahmad

it is the 54% of dry volume
1m3 wet volume = 54% dry volume
1 :1.5 : 3
1+(54%) x 1= 1+0.54 = 1.54
cement = (1x1.54) / 5.5
sand = (1.5x1.54) /5.5
aggregate = (3x1.54) /5.5

Answer / rdshah

You want to know the harden concrete ingredients then do petrographic test and get all ingredients of 1 m3 concrete

Answer / mari2selvan@yahoo.co.in

curing

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