If the load of transformer is getting more than its
rating,,,than how to overcome this problem? Suppose thee
rating of transformer is 315kva and the load is going
beyond than the rating say around load: 352kva...
Than how can we solve this problem without deducting the
load.
Answers were Sorted based on User's Feedback
Answer / mohammed asif
Dear Tech,
Transformer secondary side should be relay and breakers.
so when load are 80 to 90% as per relay setting breaker
will trip.
Transformer designed 315KVA means, you canot get more then
full load from this transformer. if you should have to get
more then full load means you may add parallel transformer.
it will give you more efficiency for your output.
| Is This Answer Correct ? | 20 Yes | 1 No |
Answer / sagar hingmire
Dear friend,
If this thing is possible then no one will take the
required rated load equipments. Everyone will use under
rated equipments.
In your case only one thing is possible ie differentiate ur
load in three categaries 1.Important,2.Not much
important,3.Not important.
So when ever ur load goes beyond 315 kVA switch off type no
3 load categari.Only this is the solution.
| Is This Answer Correct ? | 16 Yes | 1 No |
Answer / subh
Used Forced Cooling. But as per IEC 76 transformer are
designed for continuous operation at 105 % of the rated
load without exceeding guaranteed temperature rise.
| Is This Answer Correct ? | 10 Yes | 2 No |
Answer / prakash kumar
actually this is not because the transformers are rated to
work at the rated KVA levels above their Kva levels the
winding will undergo heated temperature and the above
condition is not possible this will result in burning of the
windings
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / v sridhar
in my view, whenever the load of a transformer is increased
there is a corresponding increase in its current as in our
case load is surpassing the rated value of the transformer
the current too will surpass the rated value causing the
load losses to increase beyond permiisible value causing
excessive heating of the coils, etc if this heat is not
dissipated quickly only then the problem of burning of
coils will arise, if by means of forced cooling etc we are
able to disssipate heat faster then the problem can be
solved to certain extent atleast the coils won't get burn.
Although the efficiency will go down as pointed out by
previous posts. Because in rural parts of india overloading
of distriution transformers is a very common phenomena...
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / ch.nikhil
first of all check whether the txer is taking load on its
two phase or 3 phse ...And arranging the proper cooling to
the txer at lst fr 15 min and check the load will become
less or not by reducing its temp this one solution (or)
check the aproximate relay setting whether it was acting or
not and the txer must be tripped and the proper testing like
ratio test and sht ckt tst must be conducted.
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / joy banerjee
Dear Subh
When the transformer is overloaded the insulation becomes
weak resulting in lower life of the tarnsformer. Moreover
the cables will also get overheated and may catch fire.
Also as mentioned by Kaushal the efficiency will also
decrease. Hence the answer should be as per SAGAR's or
ASIF's reply.
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / m thiyagarajan
by upgrading the cooling systems if it is onaf change it to
OFAF and OFWF We can go to maximum load as load increases
current will be high as current is it will produce more
heat so by reducing the heat we can achiieve it
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / sam
yes we can. By changing the power factor. we can keep load
constant. MW = MVA * PF.
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / kumar
Imagine 352 kva load operating at the pf of 0.8. If you're increasing the power factor to 0.95 by using static or synchronous capacitor the the kva will reduce to 274 kva and the transformer now meet the demand comfortably
Apart from this the other method is to connect another transformer in parallel with the existing one
| Is This Answer Correct ? | 1 Yes | 0 No |
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