Answer / rajan

U0 * 4 = 33/ 1.732

= 19.05 * 4
= 76KV

Answer / dhanraj

For 33 Kv cable DC hi pot test can be done like (2*E+1)1.414
here E=Voltage , 1.414 is the root 2 value.
Now (2*33+1)=67Kv
Then 67*1.414=94.738 Kv this is 100% of cable test.
In manufacturing factory they will test up to 80% of the voltage in that 100% (94.73*0.8)=75.79 Kv.
But in consumer side they will test up to 80% of voltage that injected in the factory voltage (75.79*0.8)=60.64 Kv.
Now 60.64 Kv is apply for 3 mins maximum.

Answer / michael aliganga

CABLE FACTORY AC TEST VOLTAGE =2E+1kV= 2X35+1= 71kV
DC HIPOT TEST:
CABLE INSTALLATION TEST DURING AND AFTER = ET= EF X 1.8 X 0.8
ET = 71 X 1.8 X 0.8 = 102kV, ICEA DC FIELD TEST VOLTAGE
(ICEA S-97-682) IS 100 kV FOR 35 KV SHIELDED POWER CABLE.

EF=CABLE MANUFACTURERS RECOMMENDED FACTORY AC TEST VOLTAGE
IF NOT AVAIABLE USE 2E+1KV
1.8 AC TO DC CONVERSION FACTOR (QUITE COMMON)
0.8 CONVERSION FACTOR FOR DERATING FROM FACTORY TESTING TO
ACCEPTANCE TESTING.

Answer / manohar

Hipot test conduct for 33kV cable is 1.5 times of rating
voltage in DC(49kV approx will be apply for 1 minute.)

Answer / martin thomas

Iec code
Ac= (2 x e) 1
Dc={(2 x e) 1} x 1.414
1.414=sqrt (2)
E= rated voltage

Aramco std

Dc =4 x u
U= phase voltage

Answer / b.gusain

Uo X 4 as per ICE

Answer / jagan

33kV cable hipot Test
33*2+1=67
67/√3=38.68 for single cable
38.68*√2=57.8 for diode dc convert RMS
57.8*0.8=46.3 for dielectric % reduce by year
Finally apply new cable 46.3KV /phase

Answer / chandan gupta

75.790 kv dc

Answer / a.shiva krishna

AC Hipot test voltage = Nominal input voltage * 2 + 1000
DC Hipot test voltage = AC Hipot test voltage * 1.414
for 33kv
ac hipot v/g = 33000*2+1000 = 67kv
dc hipot v/g = 67000 * 1.414 = 95kv

Answer / raveendra

(2E+1)=67 kV FOR AC HIPOT ( 1 minute test)
67*1.7 = 113.9 DC HIPOT ( i minute test)

for aged cables generally we will apply 65% of the above

What is the name of transformer oil?

18 Answers  

How does a digital electronic meter work??????

0 Answers  

If a transformer primary winding operates at 240v, the secondary at 120v and the load is 1500w & the transformer is rated at 92% efficient, what's the current flowing through the primary winding of the transformer? What is the formula for finding this?

0 Answers  

what is meant by rotating magnetic filed

0 Answers  

Brief use of isolation transformer & how it works.

1 Answers  

What are the uses of MCB & ELCB ?

2 Answers  

losses in transmission lines ?

0 Answers  

For refrigerators the motor current is raised beyond its rating on both conditions when the voltage of the system is more(say 270v) than the rated voltage(220v) as well as when the voltage of system is less(say 160v) than normal voltageof 220v, why explain?

0 Answers   Electrical Tech, UPSE,

if a single phase 3 hp submersible pump of Crompton Greaves is moving in reverse direction and sometimes it moves in rigth direction ,then what may be the cause....

2 Answers   Crompton Greaves,

STATE USE OF ARC RUNNERS & SPLITTERS ?

0 Answers  

WHICH TYPE OF TRANSFORMER USED IN SWITCHYARD IN POWER PLANT?

15 Answers   GE, Lanco, NTPC,

Metal covered multiconductor cables shall employ a marker tape located within the cable running for its complete length in lieu of cable surface marking. Is it true or false?

0 Answers