Answer / kishore kumar

Input is insufficient.size of the column is missing.
If size of the column is 300 x 300 mm, then the volume will
be
= 2x1.7x0.15 + (0.5-0.15)/3 x ((0.3x0.3+2.0x1.7+sqrt
((0.3x0.3)(2.0x1.7))
=0.981 m^3

Answer / vishal gajjar

h(=D-d)\3 * A1+A2+SqrtA1A2 = Q1
A1*A2*thickness = Q2

Q = Q1 + Q2.

Answer / suresh,trichirapalli

Q1=2.1*1.7*0.5
Q2=(0.5-0.15)/3*((A1+A2)+(SQRT A1*A2))
A1=Area of bottom portion
A2=Area of top portion
TOTAL QTY=Q1+Q2

Answer / s s grewal

Before calculating the quantity of concrete required for size of pillar or size of footing at (D=0.5 m)



Formula :- L X B X d + D-d/3 x A1 + A2 + √(A1 X A2)

Answer / manpreet singh

suppose area at bottom A1 = (AxB) and area at top A2 (axb), where A,B,a,b are the respective lengths of footing top and bottom. further D is total depth and d is small depth of footing

formula is A1xd + (D-d)x(A1+A2 + sqroot {(A1xA2)/3}

Answer / r. dilli babu

Input is insufficient.size of the column is missing.
If size of the column is 300 x 300 mm, then the volume will be
=h/3(A1+A2+Sq root of A1square+A2square)
=((.5-.15)/3)(.09+3.4+(sq root of(.09 square + 3.4 square)))
=.116(3.49+(sq root of (11.5681))
=.116(3.49+3.401)
=.116*6.891
=.799 cum

Answer / sagar mistry

Here you have not given the column size.
So we assume column size 300mm X 300mm.
There is an Offset after the periphery of column & it is 75mm.
Rectangular Part
=L X B X H
=2 X 1.7 X 0.15
=0.51 cum
Trapezoidal Part
=(h/3)(A1 + A2 + SQRT ( A1 X A2 )
=((0.5-0.15)/3) ((2 X 1.7) + ((0.3+0.075)+(0.3+0.075)) + SQRT ((2 X 1.7) X ((0.3+0.075)+(0.3+0.075))
=0.12 ( 3.40 + 0.75 + 0.70 )
=0.57 cum
Total Concrete
=0.51 + 0.57
=1.08 cum

Answer / ashish parasiya

Question is not complete because one must require top are to calculate volume for trapezoid.

Answer / r. ansari

Formula for trapezoidal footing quantity
Q = h/3{(a+b)+√ab}, a&b is area of bottom and top portion
=0.5/3{2x1.7+0.15x0.15+√3.4x0.0225}
=0.583 Cu.m.

Answer / r. suresh

Input is insufficient.size of the column is missing.
If size of the column is 300 x 300 mm, then the volume will be
=H/3(A1+A2+sq root of A1+A2)
=((0.5-0.15)/3)(3.4+0.09+ Sq root of 3.4+0.09)
=0.621 Cum

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