Answer Posted / manpreet singh

suppose area at bottom A1 = (AxB) and area at top A2 (axb), where A,B,a,b are the respective lengths of footing top and bottom. further D is total depth and d is small depth of footing

formula is A1xd + (D-d)x(A1+A2 + sqroot {(A1xA2)/3}

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