Answer / ashok kumar chaudhary

Dear Sir,

SOLUTION :-

=((LxBxd)+(LxBxD/2))M3
Here L=2.0M
B=1.7M
d=0.15M
D=0.50M
((2.0x1.7x0.15)+(2.0x1.7x(0.50-0.15)/2))
=((0.51)+(3.4x(0.35/2))
=((0.51)+(0.595))
=1.105 M3 Ans.

Answer / anand shinde

h=(D-d)

(D-d)/3x(a1+a2x(under root a1xa2)

Answer / banambar pradhan

Dear all,

DURING THE PERIOD OF CONSTRUCTION TRAPIZODIAL COMES OVER THE
RECTANGULAR.
FORMULA IS-SQUARE+TRAPEZOIDAL

SQUARE =2X1.7=3.4XDEPTH 0.15=0.51 M3

TRAPEZOIDAL=H/6(A1+A2+4((A1+A2/2)^2))

SO=0.5/6(2^2+A2VALUE NOT GIVEN IN THIS QUESTION+4(2^2+A2
VALUE NOT GIVEN/2)^2))
IF A2 VALUE COULD HAVE GIVEN THEN WE CAN GET THE ANSWER EASILY

Answer / naresh

u can calculate easily
suppose in trapezoidal footing we always find d &D
D - l * b * h
d- bottom l & b
top l& b after than calculate center of top & bottom
lets define l = 2m b =2m bottom
l = 1m b = 1m top then centre of both 1.5 × 1.5 multiply by half d .

Answer / karthikeyan

Volume = ((D+d)/2)*B*L
= ((0.5+0.15)/2)*1.7*2
= 0.325*1.7*2
= 1.105 cubic meter

Answer / mohd.younus ali , je (pr )

Top Length = L1
Bottom Length = L2
Top Breadth = B1
Bottom Breadth = B2
Depth = D

Then simple formula is
(L1+L2)/2=L
(B1+B2)/2=B
The Quantity of Concrete is = L * B * D

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