Answer / v.parthiban

a1+b1+root of a1*b1*h/3 footing size 7*7m 30cm*30cm
a1=49 b1=0.12m h=.3m
49+.12+root of 49*.012 *.3/3
49.12 + 2.425*.10
51.545*.10= 5.155cum

Answer / mohammed sadiq

Answer is 1.1053 m3

Answer / umesh gumme

avg of D & d=0.5+0.15/2=0.325
size of footing 1.7*2 no of footing assume 5
no*(avg+D)*(avg+D)*(D-d)
5*(0.325+0.5)*(0.325+0.5)*(0.5-0.15)
5*0.825*0.825*0.485=1.65 m cube

Answer / habesingh barde

V=h/3(A1+A2+(under rootA1*A2)
where, h=hieght of trepezoidel
A1=area of lower shap
A2=area of upper shap

Answer / abdul kohinoor

 a+b 
where a= l*b*h

b= h/3[(A1*A2)+underrood A1+A2

Answer / ananth

h/3(a1*a2)+root of a1^2*a2^2
a1-area of bottom
a2-area of top
h-over all height

Answer / bibekananda mishra

Volume of Trapezoidal footing = [(B+D)/2*d]*l
= [(1.7+0.5)/2*0.15]*2= 1.1*0.15*2= 0.33Cum

Answer / deepak

isolated and combined footing formula

Answer / mohan kasabe

formula:

sum of two parallel side
------------------------X perpendicular distance
2

suppose side A-2m & B-1.7
sum of D & d (.5+.15 )=0.325

(2+1.7)/2*0.325=0.601 cum.

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