how do we find the nos of bricks in 1 m3 brick masonary
Answers were Sorted based on User's Feedback
Answer / ghyar
Modular brick size is 19*9*9cm. It's size with mortor is
20*10*10, therefore No. of bks = 1/0.2*0.1*0.1 cm = 500 Nos.
| Is This Answer Correct ? | 152 Yes | 19 No |
Answer / srinivasa rao.d
the standard brick size is 230X100X75mm. After leaving the
mortor joints will come around 500 nos.
| Is This Answer Correct ? | 80 Yes | 26 No |
Answer / nagori salim
For Brick size: 19*9*9
with mortar layer size of brick is taken as 20*10*10
Now,
No.s of bricks = 1(cumec)/(0.2*0.1*0.1)
= 500 No.s
| Is This Answer Correct ? | 55 Yes | 9 No |
Answer / ravi shankar prasad
The standard size of brick we come across daily
construction work is 225*125*75 (in MM. The volume of 1
brick is equal to 0.002 mm3. So, for 1 m3 the number of
brick will be equal to 1/0.002 i.e. the answer is 500.
| Is This Answer Correct ? | 41 Yes | 13 No |
Answer / mohsin uddin jafri
Since we have 2 Standard size's of Bricks i.e,
i) 19x9x9 (in cm) &
ii) 20x10x10 (in cm)
For both these sizes of bricks we go for 10mm thick mortar
joint for all faces of the brick so the size of brick
changes to 21x11x11 and 20x10x10 respectively.
Now to calculate number of bricks in 1 Cu.M.
i) for 19x9x9: =(1 in Cu.M)/((0.20x0.10x0.10) in Cu.M)
=(1)/(0.002)
=500 Bricks.
| Is This Answer Correct ? | 38 Yes | 14 No |
Answer / s.mohamed imthiyaz
Simple method according to my view.........
BRICK SIZE=0.2*0.1*0.1
By multiplting it you will get 0.002
Now you want to find for 1m3
Divide 1m3/0.002 = 1 / 0.002
THEN YOU WILL GET THE ANSWER
AS. 500.......thats it.............
| Is This Answer Correct ? | 19 Yes | 2 No |
Answer / raju gohel
brick size 22.7x11.4x7.6 (cm)
with 10 mm mortar joint its size 23.7x12.4x8.6
so brick nos = quantity of brick work/size of brick with mortar
=1/0.237x0.124x0.086
=395
quantity of mortar
volume of brick for one m3
=395x0.227x0.114x0.076
=0.78 m so volume of wet mortar is =1-0.78=0.22 m3
volume of dry mortar=0.22/0.80 =0.275 thus it is 0.3 m3
proportion : 1:3 cement=0.3/1+3
=.075
=2.14 bags
sand = .3/4 x4
=0.018 m3
| Is This Answer Correct ? | 19 Yes | 10 No |
Answer / rajeeb kumar deo
Depends upon size of brick. If size is 230mmx100mmx75mm.
The total no. required is 495. 10mm mortar thickness should
keep in all face of brick.
| Is This Answer Correct ? | 17 Yes | 10 No |
how to calculate the amount of cement & sand required for plastering
how many kg reinforcement is required for G+ 1 roof slab of 1200qf slop slab with 5 inch thickness of house.
what is normally consolidated clay and over consolidated clay?
How we paste the Granite Slabs at External Wall?Is there any chemical compound material was using?
where are using of one way slab ?
For fine aggregate which is most suitable River sand or crusher sand & why ?
WHAR IS DIFFERENCE BETWEEN NOMINAL MIX & DESIGN MIX IN DETAIL
Why do we not deduct steel volume to find actual volume of concrete in practical as we have studied that,,, actual volume of concrete = volume of column- volume of steel pls explain with reference of IS code?????
Why joints are provided?
wat would be the probable interview questions and GD topics for IOCL exam?
Factor of safety for steel should be based on its yield stress or its ultimate stress and factor of safety for concrete should be based on its ultimate stress or its yield stress?
What is the quantit;(pratical method) of cement, sand, and gravel to be used in M25 grade of concrete for 1000 x 1000 x 1000 mm of sand (for cement please mention in kilos, and for sand and gravel please mention in cuft
Civil Engineering (5086)
Mechanical Engineering (4453)
Electrical Engineering (16638)
Electronics Communications (3918)
Chemical Engineering (1095)
Aeronautical Engineering (239)
Bio Engineering (96)
Metallurgy (361)
Industrial Engineering (259)
Instrumentation (3014)
Automobile Engineering (332)
Mechatronics Engineering (97)
Marine Engineering (124)
Power Plant Engineering (172)
Textile Engineering (575)
Production Engineering (25)
Satellite Systems Engineering (106)
Engineering AllOther (1379)