Answer / yogendra kumar

We can solve with size of bricks
If the size of brick is 22.86×6.98×10.795
With the size of mortar take 10mm thesize of modular size of brick is
23.86×7.98×11.795
Volume of modular size of brick is (23.86×7.98×11.795)=2245.80cm3=0.00225m3
In 1m3= 1/0.00225=445.27bricks
These bricks with the mortar
If we want the quantity of mortar
Then volume of standard brick ×total bricks with mortar= (22.86×6.98×10.795)×445.27=0.7669m3
And volume of mortar =1-0.7669=0.2331m3
Then we can find the brick masonry with=445 bricks
And without = 1/(22.86×6.98×10.795)=580 brickAnd
mortar volume we know the mortar is 1.35 for 1m3
Then for 0.2331 =0.2331×1.35=0.3146m3

Answer / er.jawed ahmad

Modular brick size is 19*9*9cm. It's size with mortor is
20*10*10, therefore No. of bks = 1/0.2*0.1*0.1 cm = 500 Nos.

Answer / muthu kumar

436

Answer / sushree

If the dimension of brick is 230*110*75
den for 1cum 527 bricks are used.
soln-1/0.23*0.11*0.075=527.

Answer / sampad

Brick size 248*121*72 total bricks i n 1m³ 389 nos

Answer / nagesh babu

But in Civil Engineering Book of Gupta it is given as 550
No's for one m3

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