Answer / lokesh ranjith

P=root3 v i cospie

I = P/root 3 . v. cos pi

Answer / rajesh tewari

CURRENT IN LT SIDE
=KVA *1000/1.732*LT VOLTAGE*COSQ


CURRENT IN HT SIDE
= KVA *1000/1.732*HT VOLTAGE*COSQ

Answer / baskaran.r

the rating KVA=Root 3*Vl*Il Apply primary and secondary
voltages to get the max. current

Answer / s.l.bhatt

If the current of one side either primary or secondary is
known than the current of other side will be in same
proportion as the volotage ratio of primary and secondary
side.
For example -for a 1000 KVA 11kv/0.4 kv transformer if there
is 1 amp. current in HT side than current in LT side will be
1x11x1000/400 i.e almost 26 amps.

Answer / thyagarajan

FOR EXP....

in 50mva trx mean
P= ROOT3 *V*I*COS

50*1000*1000=1.732*110*1000*I

I= 262.4 IN PRIMARY SIDE

50*1000*1000=1.732*33*1000*I

I= 874.8 AMPS IN SEC SIDE

Answer / mukul tyagi

V*I(HT SIDE)=V*I(LT SIDE)

Answer / raju kumar singh

Let suppose u have taken 1500 kva transformer of 11kv to 415 v u wanna be the current calculation for the both HT side and LT side. But u also think that u have connect load of the transformer 1000 kw. In this case both HT & LT SIDE power drawn is same. But this is three phase so we take formula
P equal to SQ ROOT 3 *V* I COS phai
Remember cos phai is necessary becuse of we know KVA :::: KW/ COS phai
U have connect 1000kw and its drawn full lo
ad then it wil be calculate in HT SIDE
1000*1000:::1.732*11000*0.8* I(u take power factor as0.8)
I::::65.6A
WHILE calculating in LT SIDE IT wil be
1000*1000::: 1.732*440*0.8* I
I:::1739.05A
because power drawn HT & LT SIDE depend on load connected to the transformer

Answer / balasubramanian

amps in LT side I=P/root 3 * v* cos pie
amps in HT side I=P/root 3 * v* cos pie

Answer / awadhesh kumar

KVA= VI/1000

Answer / manoj kumar

I=HTV/LTV

what you mean by vector group of a 3 ph transformer

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