how we can calculate the transformer size.
Answers were Sorted based on User's Feedback
Answer / madhu253
Transformer size is depends upon the load.
For example
Take one building having load of 630KW
Now we can calculate the t/f size of the building
KW=KVA*P.f
630=KVA * 0.8
KVA = 630/0.8
KVA = 787.5 KVA
So the Transformer size is 800KVA
| Is This Answer Correct ? | 131 Yes | 21 No |
Answer / sachin
actually at the time of transformer rating decided the
following factor to be consider
1.Connected Load
2.Power fACTOR
3.fUTURE eXPANSION
KW=KVA*P.f
630=KVA * 0.8
KVA = 630/0.8
KVA = 787.5 KVA
So the Transformer size is 800KVA
THIS CALCULATION IS EXACTLY CORRECT
BUT FOR FUTURE EXPANTION WE CONSIDER 30 % MARGINE FOR THAT
| Is This Answer Correct ? | 80 Yes | 13 No |
Answer / sanjay
The transformer sizing depends on (i) Continuous load +
(ii) Intermittant Load + (iii) 30% spare capacity.
With this you will get the required KVA size of the
transformer. Apart from this the consideration shall be
also on the type of load that the transformer shall feed.
In case of motor consideration shall be given to the
loading during starting of the biggesr motor along with hoe
many motors to be started at any one time.
| Is This Answer Correct ? | 13 Yes | 0 No |
Answer / tarun
Check the following
1.) Max connected load
2.) Type of load
3.) impedence drop as per IS
4.) Drop for cable used
5.) Load factor
6.) transformer efficency
7.) % loading
8.) provision for future expansion
| Is This Answer Correct ? | 6 Yes | 4 No |
Answer / narendra
Check the following
1.) Max connected load
2.) Max demand
3.) Load factor
4.) transformer efficency
5.) % loading
6.) provision for future expansion
Example
Total Connected Load in kW 870.00
Total Maximum Demand in kW (80% of CL) 696.00
Total kVA @ 0.8 PF 870.00
Total kVA @ 0.9 Load Factor 783.00
Transformer Capacity Chosen 2000
| Is This Answer Correct ? | 14 Yes | 13 No |
Answer / satya mahesh
load factor(LF) and utilization factor(UF) will play a
major role in transformer selection.
Connected load-4810
Maximum demand in a month-1582 Amps
Average load which will be the average of running loads
came in a month-1173 Amps
LF=average load/max demand
=1173/1582
=0.74
UF=No.of hours running Equip/total hours in a month
=(30*20)/(30*24)
=600/720
=0.83
Transformer size= Connected load X LF X UF
=4810 X 0.74 X 0.83
=2954 Amps
for 2954 Amps 2500 KVA(3484 Amps) transformer was suitable
in continution to the future loads also.
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / sakhile benedict mbhele
(Volt X Amp X 1,732)รท1000= KVA
| Is This Answer Correct ? | 3 Yes | 3 No |
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