Answer / prashant verma

if A is length and B is breath and H is total height of trapezoidal footing and a' and b' is size of column n h is trapezoidal portion height.
then total qty of concrete is=A*B*(H-h)+[{h/3{a^2+b^2+(ab)^1/2}]
where a=A*B
b=a'*b'

Answer / ghantola

Right formula is = V = [L X B X d] + h / 3 [ A1 + A2 + ROUTE UNDER A1 A2 ] where , l = length , b = breadth , d = bottom depth , h = D - d , A1 = bottom area , A2= top area (ii) is = V = [L X B X d] + h/6(A1 + A2 + 4 Am) where , h = D - d , A1 = bottom area , A2= top area, Am = Mean of Top and Bottom Area 

Answer / satya.mvvs

It can be find by averaging method

By averaging the width / length of the the footing

Answer / ajay saini

if the area of base is A1 and the area of top is A2 then the volume=h/3(A1squr+A2squr+under the rootA1xA2)
nOW QUANTITY(KG)=Volume x Density of concrete
the density of concrete Varies on different conditions but we can take this 1500-2350 kg/cum

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