Answer / dharmesh patel

we can only calculate the quantity in m3 only after that we
can converet in c.ft.
1/4 x 1.54 x 28.8= 11.08 bags cement for 1 m3 for the ratio
of 1:1:2
s0 731 cft = 20.719 m3 * 11.08 = 229.570 bags cement used
1/4 x 1.54 = .385 m3 sand for 1 m3
so 20.719 m3 x .385 = 7.976 m3 sand required in 731 sq .ft
2/4 x 1.54 = 0.77 m3 chips ( aggregate ) for 1 m3
so 20.719 m3 x 0.77 = 15.953 m3 chips required in 731 sq .ft

Answer / vijayababu`

M25 – 1:1:2
Total parts – 4
Cement Required for 1 cum =1/4X1.57X1440
      = 0.393X1440 = 567kg/cum
      = 11.34 bags/cum

Answer / sumanth

we can only calculate the quantity in m3 only after that we
can converet in c.ft.
1/4 x 1.54 x 28.8= 11.08 bags cement for 1 m3 for the ratio
of 1:1:2
s0 731 cft = 20.719 m3 * 11.08 = 229.570 bags cement used
1/4 x 1.54 = .385 m3 sand for 1 m3
so 20.719 m3 x .385 = 7.976 m3 sand required in 731 cu .ft
2/4 x 1.54 = 0.77 m3 chips ( aggregate ) for 1 m3
so 20.719 m3 x 0.77 = 15.953 m3 chips required in 731 cu .ft

Answer / chetan patel

for 1 cmt cont.of 1:1:2


cement:1.52/4=0.38/.035=10.8
Sand :0.38 cmt
Agg :0.38*2=0.76 cmt

So for 731/35.31=20.70 cmt

C :20.70*10.8=224 bag
S :20.70*0.38=7.86 cmt
A :20.70*0.76=15.73 cmt

Answer / gurubardhan kumar

We have total 735cu.Ft
Ratio of m25= 1:1:2
Now calculate
Cement
1/4x1.54=.385
0.385x1440=554.4kg
554/50=11.08
731/35.314=20.7
20.7x11.08=230 bag

Sand
1/4x1.54=.385
0.385x20.7=7.969cuft

Aggregate
2/4x1.54=0.77
0.77x20.7=15.99cuft

#Ingredient=1.54

Answer / er. tiwari karan

M25:: 1:1:2 Total parts is 4 Cement part is 1/4
Dry Volume of M25 is approx 1.57 times of total volume
Density of Cement is 1440
Cement Required for 1 cum =1/4X1.57X1440=565.2 approx cu. mtr.
for Bags (india cement bags) is of 50kg so 565.2 kg /50kg = 11.304 bags per cu. mtr.
So as with sand
dry volume if always 1.57 for required volume
and aggregate sole qty of aggregate if crushed to get 1 cu. mt we required 1.57 cu.mt

Answer / s jaikumar

For 1m3 of 1:1:2
Cement 1.5/4=0.375/0.036=10.41
Sand 0.37
Agg 2 *0.37 =0.74

So for 731cft /35.28=20.71
Cement is used 10.41*20.71=215.59 bags
Sand is used 0.37*20.71=7.66m3
Aggregates is used 0.74*20.71=15.32m3

Answer / pushparaj

How much cement bags required (m-25 grade) for 1000cft
And also how to calculate
Thank you

Answer / pervaiz

we have total 731 cu.ft
Now calculating
Cement
1/4x1.54x731 = 281.43/1.25 = 225.14 bags
Sand
1/4x1.54x731 = 281.43 cuft
Crush
2/4x1.54x731=562.87 cu.ft
Now verifying

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