9*8m slab 1:2:4 ratio use for M20 mix how much cent is
require it will become in cum but i want bags.
Answers were Sorted based on User's Feedback
Answer / k. bu.babu
basically slab size given;9*8
what is thickness of slab?
O.k Assume thick:0.100 m
volume of concrete=9*8*.1=7.2 Cu.m
dry materiels coeff. =1.52
M20 mix 1:2:4
cement=1.52*(1/(1+2+4))*1440=312.68 kgs.=6.25 bags
total bags required to volume=7.20cum*6.25babgs=45bags
| Is This Answer Correct ? | 44 Yes | 0 No |
Answer / harathi nitin
9m x 8m x 0.1m = 7.2cum
1.52/(1+2+4) = 0.217cum
sand = 0.217 x 2 = 0.434cum
agg = 0.217 x 4 = 0.868 cum
cement = 0.217 x 30 = 6.51bags
for 1cum = 6.51 bags
for 7.2cum = 6.51 x 7.2 = 47 bags
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / sandeep bhardwaj
The Nominal mix for M20 is 1:1.5:3 not 1:2:4,all above answers
are correct,but you shoudd have to calculate by this ratio.
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / sahilshah.civil@gmail.com
Question was wrong M 20 have nominal mix proportion (1:1.5:3) not mix proportion (1:2:4)
For Mix M 20
Qty of Slab 7.2 Cu m after consider slab thickness 0.1 m
Cement : 57 Bag
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / sundarapandiyan
Bulk material qty for one cum conc=1.52 cum(using 20mm and lesser size aggrigate)
Concrete ratio 1:2:4 = 7 part
cement =1 part
for 9x8m = 72 sqm
assume thickness as =100mm
so cc qty=9X8x0.1=7.2 cum
cement= (7.2x1x1.52)/(1+2+4)=1.563 cum
bulk cement density= 1440 kg ( for clarification cement density mean specific gravity =3.15 mean 3150kg /cum)
so cement in kg=1440X1.563 =2250.72kg
cement in bag= 2250.72/50=45.014 bag can assume as 45 bag.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / johnmiya shaik
M.20 mix(1:2:4)
1 2 4=6
1.52/6=0.253333
(Cement wet density to dry density ratio)
(One cement bag=0.035cum/1.225 cft)
0.253333/0.035=7.238095
Slab area=72sqm
Assume thickness=100mm
So concrete qty=9x8x.1=7.2cum
Cement bags=7.2 cumx7.238095=52.11 bags/2605.714kg
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / binubal123
Volume of Conc needed=9*8*0.01(assume)
=7.2Cum
M20 mix (1:2:4)
material
cement by vol=7.2*1/(1+2+4)
=1.028
Sand By Vol=7.2*2*1/(1+2+4){2*1.028}
=2.05
Agg By vol~4*1.028
=4.114
Cement in bag req=1.028*308.53(Cement Constant frm Practical Info for Quantity Surveyor P.T.Joglekar) =317.34Kg=317.34/50=6.36bags
| Is This Answer Correct ? | 1 Yes | 5 No |
define the grain size analysis and what is the silt size?
what is meant by shear center?????
how many kg sand is requried for plastring in 100 sqft?
WHAT IS NON DESTRUCTIVE TEST?PLEASE GIVE ME THE PROCEDURE?
What is the volume of sand in per cubic meter if we have a design mix of concrete is 1:2:4 (by volume).
Do you know differenence between design mix and nominal mix?
What is IS Code ? And What is IS - 9301 ?
Please provide detail I.S standard code for using crush sand instead of river sand for plaster and concrete grade M15, M20, M25 and M30 and its mix design
which concrete grade has highest strenth and what is its comosition?
what is the ideal construction joint for slab?
how to calculate the density for high density concrete ? or is it same as the density of RC?
Moisture content calculation for diff mix ratio's ??
Civil Engineering (5086)
Mechanical Engineering (4456)
Electrical Engineering (16639)
Electronics Communications (3918)
Chemical Engineering (1095)
Aeronautical Engineering (239)
Bio Engineering (96)
Metallurgy (361)
Industrial Engineering (259)
Instrumentation (3014)
Automobile Engineering (332)
Mechatronics Engineering (97)
Marine Engineering (124)
Power Plant Engineering (172)
Textile Engineering (575)
Production Engineering (25)
Satellite Systems Engineering (106)
Engineering AllOther (1379)