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how many cement use for 1cum concrete for 25Grade.

Answers were Sorted based on User's Feedback



how many cement use for 1cum concrete for 25Grade...

Answer / somu

360

Is This Answer Correct ?    5 Yes 6 No

how many cement use for 1cum concrete for 25Grade...

Answer / pradeep kumar

M25, actually it is design mix so we cannot say exact ratio for this grade but approximately the ratio is 1:1:2,

for preparing 1m3 of concrete, 1.5 m3 need to be taken.

Hence, 1:1:2 - 1+1+2=4,

Volume of the cement= 1/4*1.5 = 0.375
Unit weight of cement = 1440 kg/m3 
so weight of cement = 0.375*1440 = 540 Kgs.

Hence, 1 m3 of M25 grade concrete is required 540 kgs of cement 

Is This Answer Correct ?    7 Yes 8 No

how many cement use for 1cum concrete for 25Grade...

Answer / ms

M25=1:1:2
50kg cement=1.25 cft
1.25cft=5cft concrete of M25

So. =1.25÷5
=.25 cement is the 1cft concrete

=.25×35.28
=8.82cft cement/M3
=8.82×41
=361.62÷50
=7.23 bags is required ok

Is This Answer Correct ?    2 Yes 4 No

how many cement use for 1cum concrete for 25Grade...

Answer / muhammad rizwan hashmi (pakist

M25 Ratio of concrete = 1:1:2
Sum of ratio =4
Quantity of Cement (dry material) = 1/4*1.54
= 0.385 cu.m
1 bag = 0.0354 cu.m
= 0.385/0.0354
= 10.88 bags
1 bag = 50 kgs
Cemeent: 10.88 *50 =543kgs

Is This Answer Correct ?    14 Yes 27 No

how many cement use for 1cum concrete for 25Grade...

Answer / srinu

m25 grade of concerete 1:1.5:3
total 1+1.5+3=5.5
cement volume 1440m3
360 kgs cement

Is This Answer Correct ?    8 Yes 24 No

how many cement use for 1cum concrete for 25Grade...

Answer / raman

M25:-1:2:4 mix
and 6.5 bags about
means 325 kgs

Is This Answer Correct ?    14 Yes 42 No

how many cement use for 1cum concrete for 25Grade...

Answer / bala

* M25 - 1:1:2
Cement Reqd is - 610Kgs per cu.m(12.2Bags)

Is This Answer Correct ?    8 Yes 51 No

how many cement use for 1cum concrete for 25Grade...

Answer / vijay

M25 -1:1:2
volume of coarse aggregate in 1cum=0.95cum
vol. of sand =0.95/2=.475
hence vol. of cement=vol. of sand
vol. of 1 bag of cement =0.035cum
no. of bag required=.475/.035=14 bags
cement=50*14=700kg

Is This Answer Correct ?    5 Yes 48 No

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