Answer / hari

for M15 proportion is 1:2:4
dry volume of concrete in 1 cum = 1.54
cement qty - 1.54/(1+2+4)*1 = 0.22cum
Fine Agg - 1.54/(1+2+4)*2 = 0.44cum
coarse Agg - 1.54/(1+2+4)*4 = 0.88 cum

check any proportion - (0.22+0.44+0.88) = 1.54cum

Answer / r. dilli babu

M15 (1:2:4)
=((0.45/sand ratio)*1440)
Cement=324 kg , 6.48bags, 8.1cft
sand=16.2 Cft
Mattel=32.4 Cft

Answer / mangesh

for M15 proportion is 1:2:4
assume wet volume 1 m3 of work
to produce 1 m3 of wet volume we need 1.54 dry volume
cement qty=1.54/1+2+4=0.22 m3
hence no of bag=0.22*1440/50=6.33 nos
sand qty=0.154*2=0.308 m3
agg qty=0.154*4= 0.616 m3


40 mm is max size of agg & it is the std value

Answer / n3

for M15 proportion is 1:3:6
assume wet volume 1 m3 of work
to produce 1 m3 of wet volume we need 1.54 dry volume
cement qty=1.54/1+3+6=0.154 m3
hence no of bag=0.154*1440/50=4.44 nos
sand qty=0.154*3=0.462 m3
agg qty=0.154*6=0.924 m3


40 mm is max size of agg & it is the std value

Answer / raju

for M15 proportion is 1:3:6
assume wet volume 1 m3 of work
to produce 1 m3 of wet volume we need 1.54 dry volume
cement qty=1.54/1+2+4=0.22 m3
hence no of bag=0.22*1440/50=6.33 nos
sand qty=0.154*2=0.308 m3
agg qty=0.154*4= 0.616 m3

it is possiblee to produce concrete with out cracks...

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