Answer / tariq afridi

for example a square coloumn
no of bars are #22
dia of bars $6 no / 6 sooter bars
lenght of each bar is 10 ft.
solution.
weight of 5 no bar per/ft is 1.043lbs
firstly find rft 22*10 = 220rft 220* 1.043= 229.46 lbs
number of rings
height/centre to centre distance.
10'/.5' = no of rings are 20.

Answer / sumanth maharana

Length of the Beam and column. min "5"inc Depend height.Yes weight of column including rings

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