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#define square(x) x*x

main()

{

int i;

i = 64/square(4);

printf("%d",i);

}

Answers were Sorted based on User's Feedback



#define square(x) x*x main() { int i; i = 64/square(4); print..

Answer / susie

Answer :

64

Explanation:

the macro call square(4) will substituted by 4*4
so the expression becomes i = 64/4*4 . Since / and * has
equal priority the expression will be evaluated as (64/4)*4
i.e. 16*4 = 64

Is This Answer Correct ?    231 Yes 14 No

#define square(x) x*x main() { int i; i = 64/square(4); print..

Answer / boby

64

Is This Answer Correct ?    20 Yes 1 No

#define square(x) x*x main() { int i; i = 64/square(4); print..

Answer / mayur rangade

64

Is This Answer Correct ?    13 Yes 0 No

#define square(x) x*x main() { int i; i = 64/square(4); print..

Answer / manish

16

Is This Answer Correct ?    2 Yes 13 No

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