void main()
{
static int i;
while(i<=10)
(i>2)?i++:i--;
printf(“%d”, i);
}
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Answer / susie
Answer :
32767
Explanation:
Since i is static it is initialized to 0. Inside the while
loop the conditional operator evaluates to false, executing
i--. This continues till the integer value rotates to
positive value (32767). The while condition becomes false
and hence, comes out of the while loop, printing the i value.
| Is This Answer Correct ? | 7 Yes | 2 No |
Answer / prashanth
As i is static, it initially stores value 0.
as 0<=10 and in next stmt 0>2 is false so i-- is executed..
the loop continues till i=-32768 and when i=-32768 then
-32768>2 is false so i-- is executed..
As -32768-1 is equal to 32767. so i=32767 now..
while condition fails and it comes out of loop..
so the ans. is 32767.
| Is This Answer Correct ? | 4 Yes | 0 No |
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