Answer / susie

Answer :

30,20,10

Explanation:

'{' introduces new block and thus new scope. In the
innermost block i is declared as,

const volatile unsigned

which is a valid declaration. i is assumed of type int. So
printf prints 30. In the next block, i has value 20 and so
printf prints 20. In the outermost block, i is declared as
extern, so no storage space is allocated for it. After
compilation is over the linker resolves it to global
variable i (since it is the only variable visible there). So
it prints i's value as 10.

There were 10 records stored in “somefile.dat” but the following program printed 11 names. What went wrong? void main() { struct student { char name[30], rollno[6]; }stud; FILE *fp = fopen(“somefile.dat”,”r”); while(!feof(fp)) { fread(&stud, sizeof(stud), 1 , fp); puts(stud.name); } }

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