Answer / addu

#include<stdio.h>
double pow(int,int);

main()
{
int m,n;
double res;
printf("Enter the number and the power : ");
scanf("%d%d",&m,&n);
res=pow(m,n);
printf("\nThe result is = %d\n",res);
}
pow(int m,int n)
{
if(n>0)
{
return m* pow(m,n-1);
} else if (n==0){
return 1;
} else {
return (1/((double)m))*pow(m,n+1);
)
}

Answer / nagarajanselvaraj

#include<stdio.h>
int pow(int,int);
int r=1;
main()
{
int m,n,res;
printf("Enter the number and the power : ");
scanf("%d%d",&m,&n);
res=pow(m,n);
printf("\nThe result is = %d\n",res);
}
pow(int m,int n)
{
if(n>0)
{
r=r*m;
n--;
pow(m,n);
}
return r;
}

main() { int i, n; char *x = “girl”; n = strlen(x); *x = x[n]; for(i=0; i<n; ++i) { printf(“%s\n”,x); x++; } }

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abcdedcba abc cba ab ba a a

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