Answer / guest

a)

Answer / govind verma

OK I am done. reason bollean expression in if evaluate in such manner first (1||0) will execute and first expresiion of this boolean expression is one so control will not goes to chek any thing i.e whole expression evaluate as (1||0)as 1(true) now expression becom like dis if(1&&(0||1))
now (0||1) expressiion will evaluate in this expression value of left hand side of || operator is 0(false) so control goes to check further and right hand side it recieve 1 then the value of wholl expression becom 1 thn nw orignal expression looks like if(1&&1)
nw (1&&1) is evalute in this case control check both the value of the operator(&&) is one then this return 1 otherwise return 0 then orignal expression like this if(1)
1 is nonzero value this mean condition is true then code of if block will be execute which is OK I am done.

Answer / naveen kumar

ok i am gone...because in this case the condition if((1||0)
&&(0||1)
always remain true. hence the answer is ok i am done...i.e.
(a

Answer / priti soni

d

Answer / karthi

c.compile error

Under linux environment can u please provide a c code for computing sum of series 1-2+3-4+5......n terms and -1+2-3+4-5...n terms..

2 Answers  

#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d..%d",*p,*q); }

1 Answers  

main ( ) { static char *s[ ] = {“black”, “white”, “yellow”, “violet”}; char **ptr[ ] = {s+3, s+2, s+1, s}, ***p; p = ptr; **++p; printf(“%s”,*--*++p + 3); }

1 Answers  

main( ) { static int a[ ] = {0,1,2,3,4}; int *p[ ] = {a,a+1,a+2,a+3,a+4}; int **ptr = p; ptr++; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); *ptr++; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); *++ptr; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); ++*ptr; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); }

2 Answers   Persistent,

which function is used to clear the buffer stream on gcc? for example: I wrote following code on gcc #include<stdio.h> int main(void) { char ch; int a,b; printf("\nenter two numbers:\t"); scanf("%d%d",&a,&b); printf("enter number is %d and %d",a,b); printf("\nentercharacter:\t"); scanf("%c",&ch); printf("enter character is %c",ch); return 0; } in above progarm ch could not be scan. why?plz tell me solution.

2 Answers  

main() { float me = 1.1; double you = 1.1; if(me==you) printf("I love U"); else printf("I hate U"); }

1 Answers  

main() { char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

2 Answers  

Write a single line c expression to delete a,b,c from aabbcc

2 Answers   Microsoft,

#include<stdio.h> main() { struct xx { int x; struct yy { char s; struct xx *p; }; struct yy *q; }; }

2 Answers  

hello sir,is there any function in C that can calculate number of digits in an int type variable,suppose:int a=123; 3 digits in a.what ll b answer?

6 Answers  

You are given any character string. Find the number of sets of vowels that come in the order of aeiou in the given string. For eg., let the given string be DIPLOMATIC. The answer returned must be "The number of sets is 2" and "The sets are "IO and AI". Vowels that form a singleton set must be neglected. Try to post the program executable in gcc or g++ or in java.

3 Answers  

main() { printf("%x",-1<<4); }

3 Answers   HCL, Sokrati, Zoho,