Answer / manoranjan

Use of formula is always a cumbersome exercise.
In pactical 1.5A/sqmm for al,cable & 2.5A/sq.mm is
considered in practical way. means a 50sqmm Al cable will
carry at least 75A and same size copper cable will carry
125A.

Answer / satish

Thumb rule
For Al Conductor Cable Multiply Sq mm size by 1.5.
&
For Cu cable Multiply sq mm size by 4.
e.g.
70 sq mm Al Cable can take 70×1.5=105 A
&
16 sq mm Cu cable can take 16×4=64 A

Answer / gaurav

1.0 To 1.5A/sqmm for al,cable & 2.0 TO 2.5 A/sq.mm is
considered in practical way. means a 50sqmm Al cable will
carry at least 75A and same size copper cable will carry
125A.

Answer / martin

Check the CCC by any supplier's brochure.
Derate the CCC on the following parameters
Maximum Ambient temp.
Cable buried UG / on air
Clearance between adjuscent cables.
185 mm2 4 c Alu XLPE cable's ccc = 200 Amps in the Gulf.

Answer / umesh

16sq mm amps

Answer / parbat musar

Load 50 amp

Answer / devi prasad

for cu current in z sq mm = z× 4Amp
for ALU =Z×2 Amp

Answer / aloke kumar pati

My experience with electricity does not agree with the above answers. For years I have used a 1.5 sq. mm. Al service line for a load of at least 2 KW (ignoring the motor- based appliances whose initial current is much higher). This load required at least 9 amps. which came through the 1.5 sq. mm. Service line! Thus the 'thumb-rule' of multiplying sq. mm. by 1.5 to get the amperage in Aluminium cable is belied in the above instance given by me.

Answer / manoj

Measure the load connected in that cable

Answer / sbb

As we know that Resistance of conductor is calculated by

R= row*l/a
where row=specific resistance of the conductor i.e
aluminium and copper(depends of material)
l=length of the conductor
a=area of cross-section of the conductor.

And as we know that the conductivity of the aluminium
conductor is <=1 (depends upon the distance of the cable
laid avg.0.8-1) and conductivity of copper is <=1.5
(depends on cable laid. avg. 1.2-1.5).

for ex.take cable length of 180 sq.mm Al. cable

if we want to know the current carryng capacity is
180*o.9=168 A approx.

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