Answer / ramesh kalsaria

calculation Formula=cos(phi)=kw/kva

Answer / sukhvinder

connected load=375kw
kva=kw/cos phi
kva=375kw/.8
=468.75

extra load= 20% (assume) i.e 468*20%= 93.6

total 468.75+93.6=543.68 kva say 550kva

eff. 375/550*pf (0.8)*100=85%.

Answer / munish saini

KW=KVA*PF
PF=.8
KW=375
KVA=KW/PF,=375/.8=468.75KVA

20 Percent required more as eppiciency Factor
so required dg should be=562.5 KVA

Answer / virendra joshi

Dear friends,


Total Connected Load = 375 KW
KVA required @0.8 PF = 375 /0.8 = 468
Taking a 0.8 as a Demand Factor = 468 *0.8=375 KVA
Considering running of D.G set on 80% load = 3750.8=468 KVA
Considering 20% load for future expansion = 468 + 20%(93KVA)
Total KVA of D.G set = 561 KVA

you can go with 600 KVA D.G set .

Answer / srinivas

if the connected load of plant is 375kw. but any time all
the load may not be there. if peak load may be 300kw at any
instant so KVA rating of DG=KW/cos(phi) so you can take
300/0.9= 333.33 so you can take 350KVA Dg you can go for.

Answer / syed.yaseen

dear friends,

Given kw = 375
suitable kva = 375/.8 =468.75
Future extra load consider = 20% ie.. 93.75kva
total kva = 468.75 + 93.75 = 562.5
as per company designed capacity preferred is 625kva dg set

Answer / vikash gupta

calculation formula:-kva rating=kw rating/cos phi

connected load=375w
kva=kw/cos phi
kva=375w/.8
=468.75w (ans)

extra load=(468.75-375)w
=93.75watts(ans)

efficiency =375*100/468.75
=80%

Answer / sam

calculation formula is KVA= KW*Pf(cos phi)

KVA= 375*.9
KVA=337 so DG set will be more than 20% of rated KVA

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