Answer / mohammed abdul moid

Take footing F= 4 No's size 1.2m*1.2m. and 6No. of
16mmbars
take bottom bar 1.2m and depth 0.5m
Total length L= 1.2+0.5= 1.7mt*1000= 1700

Formula =[3.14*0.00000785*16/2*16/2*1700]*6(No of
bars)
=[3.14*0.00000785*8*8*1700]*6
=[2.6818]*6 = 16.09
=[16.09]*2(Top n Bottom bars)=32.08
=[32.08]*4(No of footings in plan)
=[128.72kgs]

Answer / mutual basha baig

Qty of steel(in kgs) =no.of bars×length of bar × unit wt of bar ×simillar objects.

@unit wt of bar =diameter of bar/162.

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