Answer / nadim shaikh

Multiply the size of brick and get the volume ffor e.g.
4 inch brick
= 9"x3"x4"
=0.75 x 0.25 x 0.33 =0.061875 cubic foot
Now 1÷0.061875 = 16 bricks

In any kind of BRICK WORK 33% mortar is assumed in one cubiic foot
That is in 100 cubic foot 33% Will be 33 cubic foot
Consider mortar mix ratio 1:6
Therefore for cement = 33 ÷ 7 (addition of 1 and 6)
=4.71÷1.25 (1 cement bag is 1.25 cu.ft.)
=3.768 ~3.8 bags
Sand = 4.71 × 7 = 33 cu.ft

Answer / sha

mr.Nadim...can u tell the ans correctly...how u get the 33%
...pls advice...

Answer / faisal qaseem

Dear I think the answer is incorrect and is some what like that:

Sand Qty will be 6/7*33 = 28.285 Cft
to get its dry volume 28.285 * 1.54 = 43.5 Cft

Also bricks in market are not available in standard sizes, practically its size varies and is around 8.75"*2.75"*3.75"

whereas to get the volume from the same quantities (Cft volume of all walls considering bricks only) as obtained by estimation (Autocad and Excel etc), the ration will be practically 75% and 25% and not 67% and 33%.

Answer / nadim shaikh

take brickwork as 100 percent then deduct the mortar
for e.g
6 " wall dimension 10' x 10'
10 feet divided by numbers of mortar layer which will be decided by dividing it by brick laying format for stretcher bond it will be
10' / .33 (4 inch = .33[4/12])
=30 numbers + 1 = 31 ( this was for vertical )
now for horizontal
10'/.75 = 13+1 = 14 joints
now
10' x .5 x .08 ( dimesion of mortar laid in horizontal direction) = 0.4 x 31 joints = 12.4 cu.ft
&
10' x .33 x .08 ( dimension of mortar laid in vertical direction) =0.264 x 14 joints = 3.7
add both i.e 12.4 + 3.7 = 16.1 cu.ft
if 10' x 10' x 6" = 50 cu.ft is 100 % the how much percent will be 16.1 of 50 cu.ft ..
16.1/50x100 = 32.2 say 33%
wooah .. that was quite a lecture

Answer / akoddus

100cft chips how many brick need, please calculation

Answer / nadim shaikh

iam truly sorry i forgot to add dry volume 50% into 33% of wet volume of that desired brickwork

Answer / mano

12.88 brick, 1 cum 455 bricks

Answer / usman majeed

nadim shaikh bro how can i find ( .08 ( dimension of mortar laid

Answer / ajeeth

1 cu.feet wall-9 inches
Ans
Brick without mortor:
Brick in cu.feet=(9/12)×(4.15/12)×(3/12)
= .0648 cu.feet
Brick with mortor:
(.4 Inches as mortor)
Brick in cu.feet = (9.4/12)×(4.45/12)×(3.4/12)
= .0823Cu.feet
Volume of mortor:
= Brick with mortor-brick without mortor
=.0648-0.0823
=.0175
Mortor need for one brick =.0175cu.feet
BRICK FOR ONE Cu.feet
=1/.0823
=12.15=approximately 13✓
MORTOR FOR ONE Cu.feet
=13×.0175
=.2275cu.feet
RATIO-1:6
Volume of cement:
cement=(.2275/7)×1
=.0325cu.feet
=.0325×1440/50
=.936 bags
=approximately1bag
Volume of sand:
Sand = (.2275/7)×6
= .195 cu.feet
ADDITIONAL 10 PERCENTAGE OF WASTAGE CAN BE ADDED;
after adding wastage;
Cement in bags=1.1 bag
Sand in cu.feet = 2.145 cu.feet

Answer / zahd

how did u get 16 bricks divided by 1/ 0.061875=16 brick i don't understand actually how u get 16 would u plz tell me the farmula or value to get brick or how u get 16 brick from 1/ 0.061875 ...?????

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