Answer / eng.mehboobullah

for calculating the volume of cement in this question it
also need thickess. we consider the thickness of the
plaster 0.5 inch = 0.04' thus the total volume will be 4cft.
this is the wet volume now multiplying it with constant
1.27 the dry volume will be 5.08
now sum of ratio is 5 according to the formula
1 x 5.08/5 = 1.01 cft one cement bag have volume
of 1.25 cft now dividing it on 1.25 we get
1.01/1.25 = 0.81 bags
in plaster the volume of cement depends on the thickness of
the plaster but normally it is adopted as 1/2" that is the
answer of both question change the thickness of the plaster
will change the value of volume of cement. thanks

Answer / aijaz hussain, modi builders

For plastering ceiling, thickness will be 10 mm in CM (1:3)
To cover an area of 100 sft. plastering 50 kgs is required

And for plastering the walls in CM (1:4), quantity of
cement required to cover 100 sft. 20 mm thickness will be
85 kgs.

Answer / pramod rajput

1:4 12mm thk 1beg/10 m2 and 1:3 12mm thk 1.35begs/10 m2 1 sqmtr=10.76 sqft

Answer / ahmed j

Thikness of plaster for 1st coat is roush 12mm (1.6)(1.5)(1.4)
Thikness of plaster for 2nd coat is fine 8mm (1.4)(1.3)

Area is 100sft/3.28^2=0.92
.92*.012=0.011

Sand 1cum required is 1.25cum
1.25/4=0.3125

0.01104*.3125*1440=50.19 Kgs Cement

(1.3)

Area = .92mtr sqr *.008(fine)=.0736*0.21=.0156*1440=22.48 Kgs Cement

Answer / prashanth kumar

MATERIAL REQUIRED FOR PLASTERING 100 SQUARE FEET OF CEILING WITH 12MM THICKNESS IN CM(1:3) IS 1.2 BAGS OF CEMENT AND IN CM(1:4) IS 1 BAG OF CEMENT

Answer / lawrence.m

We assume the thickness is approx. 0.5inch. So that the volume is 100sqftx0.5=50cft(1.416cum).
For 1 cum( CM1:4), 1/5x 1440= 288Kg cement required.
Therefore, 1.416cum = 407 Kg required(Approx 8 bags)

For CM 1:3, = 510 Kg (Approx. 10 bags)

residential projects,structural.

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