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#include<stdio.h>

main()

{

int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} };

int *p,*q;

p=&a[2][2][2];

*q=***a;

printf("%d----%d",*p,*q);

}



#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; ..

Answer / susie

Answer :

SomeGarbageValue---1

Explanation:

p=&a[2][2][2] you declare only two 2D arrays,
but you are trying to access the third 2D(which you are not
declared) it will print garbage values. *q=***a starting
address of a is assigned integer pointer. Now q is pointing
to starting address of a. If you print *q, it will print
first element of 3D array.

Is This Answer Correct ?    1 Yes 0 No

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