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#include<stdio.h>
main()
{
int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} };
int *p,*q;
p=&a[2][2][2];
*q=***a;
printf("%d----%d",*p,*q);
}
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Answer Posted / susie
Answer :
SomeGarbageValue---1
Explanation:
p=&a[2][2][2] you declare only two 2D arrays,
but you are trying to access the third 2D(which you are not
declared) it will print garbage values. *q=***a starting
address of a is assigned integer pointer. Now q is pointing
to starting address of a. If you print *q, it will print
first element of 3D array.
| Is This Answer Correct ? | 1 Yes | 0 No |
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