Is the following code legal?
struct a
{
int x;
struct a b;
}
Answer / susie
Answer :
No
Explanation:
Is it not legal for a structure to contain a member
that is of the same
type as in this case. Because this will cause the structure
declaration to be recursive without end.
| Is This Answer Correct ? | 1 Yes | 0 No |
char inputString[100] = {0}; To get string input from the keyboard which one of the following is better? 1) gets(inputString) 2) fgets(inputString, sizeof(inputString), fp)
how to print 1 2 3 4 5 6 7 8 9 10 9 8 7 6 5 4 3 2 1 using any loop(for or while) only once(only 1 loop) and maximum 2 variables using C.
19 Answers Cap Gemini, Infosys,
main() { signed int bit=512, mBit; { mBit = ~bit; bit = bit & ~bit ; printf("%d %d", bit, mBit); } } a. 0, 0 b. 0, 513 c. 512, 0 d. 0, -513
3 Answers HCL, Logical Computers,
main() { static int a[3][3]={1,2,3,4,5,6,7,8,9}; int i,j; static *p[]={a,a+1,a+2}; for(i=0;i<3;i++) { for(j=0;j<3;j++) printf("%d\t%d\t%d\t%d\n",*(*(p+i)+j), *(*(j+p)+i),*(*(i+p)+j),*(*(p+j)+i)); } }
Write a routine to implement the polymarker function
#define SQR(x) x * x main() { printf("%d", 225/SQR(15)); } a. 1 b. 225 c. 15 d. none of the above
There is a lucky draw held every day. if there is a winning number eg 1876,then all possible numbers like 1867,1687,1768 etc are the numbers that match irrespective of the position of the digit. Thus all these numbers qualify fr the lucky draw prize Assume there is no zero digit in any numbers. write a program to show all the possible winning numbers if a "winning number"is passed as an arguments to the function.
# include <stdio.h> int one_d[]={1,2,3}; main() { int *ptr; ptr=one_d; ptr+=3; printf("%d",*ptr); }
Is the following code legal? struct a { int x; struct a b; }
Find your day from your DOB?
15 Answers Accenture, Microsoft,
Predict the Output: int main() { int *p=(int *)2000; scanf("%d",2000); printf("%d",*p); return 0; } if input is 20 ,what will be print
struct point { int x; int y; }; struct point origin,*pp; main() { pp=&origin; printf("origin is(%d%d)\n",(*pp).x,(*pp).y); printf("origin is (%d%d)\n",pp->x,pp->y); }