Answer / rajendra kumar

#include<stdio.h>
#include<conio.h>
#define n 4
void main()
{
int A[n][n]={{1,2,3,4},{5,6,7,8},{9,10,11,12},{13,14,15,16}};
int min=0,max=n-1,i,j;
clrscr();
while(min<max)
{
for(i=min;i<=max;i++)
printf("%d,",A[min][i]);
for(i=min+1;i<=max;i++)
printf("%d,",A[i][max]);
for(i=max-1;i>=min;i--)
printf("%d,",A[max][i]);
for(i=max-1;i>min;i--)
printf("%d,",A[i][min]);
min++;
max--;
}
getch();
}

Answer / mahfooz

#include<stdio.h>
#define n 3
int main()
{
int arr[n][n]={{1,2,3},{4,5,6,},{7,8,9}};
int min=0,max=n-1,i;
while(min<=max)
{
for(i=min;i<=max;i++)
printf("%d ",arr[min][i]);
for(i=min+1;i<=max;i++)
printf("%d ",arr[i][max]);
for(i=max-1;i>=min;i--)
printf("%d ",arr[max][i]);
for(i=max-1;i>min;i--)
printf("%d ",arr[i][min]);
min++;
max--;
}
if(min==max) //this for odd case as n=3,5 etc
printf("%d \n",arr[min][min]);
return 0;
}

Answer / raghuram.a

#include<iostream.h>
#include<conio.h>
#include<stdio.h>
main()
{
int n,m,i=0,j=0,k=0,l=0,p=0,q=1,r=0,s=1,a=40,b=25,ar[100];
clrscr();
cout<<"enter n:";
cin>>n;
printf("enter array elements:");
for(m=0;m<n;m++)
scanf("%d",&ar[m]);
gotoxy(a,b);
m=0;
printf("%d",ar[m++]);
while(m<n)
{
while(i<=j)
{
i++;
a+=4;
gotoxy(a,b);
printf("%d",ar[m++]);
if(m>=n)
goto next;
}

while(k<=l)
{ k++;
b+=4;
gotoxy(a,b);
printf("%d",ar[m++]);
if(m>=n)
goto next;
}
while(p<=q)
{
p++;
a-=4;
gotoxy(a,b);
printf("%d",ar[m++]);
if(m>=n)
goto next;

}
while(r<=s)
{
r++;
b-=4;
gotoxy(a,b);
printf("%d",ar[m++]);
if(m>=n)
goto next;
}
j+=2;
l+=2;
q+=2;
s+=2;
i=0;
k=0;
p=0;
r=0;

}
next:getch();
return 0;
}

main() { char *p; printf("%d %d ",sizeof(*p),sizeof(p)); }

6 Answers  

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main() { int i =10, j = 20; clrscr(); printf("%d, %d, ", j-- , --i); printf("%d, %d ", j++ , ++i); } a. 20, 10, 20, 10 b. 20, 9, 20, 10 c. 20, 9, 19, 10 d. 19, 9, 20, 10

4 Answers   HCL,

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What is full form of PEPSI

0 Answers  

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main() { int a[10]; printf("%d",*a+1-*a+3); }

1 Answers  

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main( ) { int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}}; printf(“%u %u %u %d \n”,a,*a,**a,***a); printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1); }

2 Answers  

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void pascal f(int i,int j,int k) { printf(“%d %d %d”,i, j, k); } void cdecl f(int i,int j,int k) { printf(“%d %d %d”,i, j, k); } main() { int i=10; f(i++,i++,i++); printf(" %d\n",i); i=10; f(i++,i++,i++); printf(" %d",i); }

1 Answers  

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void main() { int *i = 0x400; // i points to the address 400 *i = 0; // set the value of memory location pointed by i; }

2 Answers  

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main() { int x=5; clrscr(); for(;x==0;x--) { printf("x=%d\n”", x--); } } a. 4, 3, 2, 1, 0 b. 1, 2, 3, 4, 5 c. 0, 1, 2, 3, 4 d. none of the above

3 Answers   HCL,

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How to count a sum, when the numbers are read from stdin and stored into a structure?

1 Answers  

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main() { int *j; { int i=10; j=&i; } printf("%d",*j); }

9 Answers   HCL, Wipro,

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main() { int i=0; while(+(+i--)!=0) i-=i++; printf("%d",i); }

9 Answers   CSC, GoDB Tech, IBM,

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main() { char *p = “ayqm”; char c; c = ++*p++; printf(“%c”,c); }

1 Answers  

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