How current is reduced in STAR connection?
Answers were Sorted based on User's Feedback
Answer / yousef madhi
Suppose That the line voltage on DELTA connection
V(line)= V
and the line current I(line)= I
as we know in DELTA connection the phase voltage equal the line voltage and the phase current equal to the line current times 1/root(3)
then V(phase)=V(line) = V
and I(phase)=I(line)/root(3) = I/root(3)
In STAR connection if again the line voltage equal to V(line)= V , the phase voltage will equal to line voltage time 1/root(3)
V(phase)=V(line)/root(3) = V/root(3)
and as per Ohm's Law (V=I*Z) and in both connection (star & Delta) we have the same winding impedance, any change in Voltage will change the current in the same amount.
so the phase current for star connection will be equal to
I(phase-star)= I(phase-delta)/root(3)
=(I/root(3))/root(3)
= I/3
and as we know in star connection the line current equal to the phase current
I(line)=I(phase)= I/3
Conclusion:
the line current in star connection is reduced by 1/3 time the line current in delta connection
| Is This Answer Correct ? | 18 Yes | 0 No |
in star connected winding net resistance across the line
voltage will be less as the winding across line volt are in
series.
in delta connected winding the net resistance across the
line voltage will be more as the winding across line volt
are in parallel. (one winding will be in parallel with
series combination of other two. so net resistance is less
than the resistance of one winding in delta)
| Is This Answer Correct ? | 16 Yes | 10 No |
Answer / vijay maurya
According to ratio line V equal to phase V upon root 3 . So
that decrease the V, decrease the current
| Is This Answer Correct ? | 8 Yes | 10 No |
Answer / sibi mathew
When motor is started there is no power. the only factors which effects the current is the impedance of the winging.
i.e. the current I=V/Z. So since the phase voltage in star connection =phase voltage xroot3,starting current is reduced to one third of delta connection.
| Is This Answer Correct ? | 3 Yes | 5 No |
Answer / abhishek goyal
STAR : decrease the voltage
decrease the torque
decrease the speed
decrease the current
as per electrical formula
| Is This Answer Correct ? | 4 Yes | 11 No |
it is possible to measurement of tension of slipring induction motor(SRIM)carbon brushes, any maesuring instruments are available in the markets.
At site, we have 30Kw motor (3 phase, 400V,50Hz) and FLC 54A as per the nameplate. At the time of starting it draws 840A instead of 390A (7.2%). As per the data sheet also its 390A starting current. it thru a dol starter from the MCC. can anyone tell what is the problem in the motor
in pf lagging means current decrease by increasing voltage is correct or not ? reason ?
What current position are you holding in your current company?
What is the difference between line drop and percentage line drop?
what is the use of earthing?
how to find Harmonics and types as per the equipemnts
how the grounding[earting] is achieved on ships.
from 33kv to 440v 2mva transformer how much full load current will be at ht side and lt side and which range of ctpt will be used?
what is REF relay?
WHY THAT THREE COLORS CHOOSEN IN 3 PHASE? WHAT IS MEAN BY RYB?
generator(Deutz 550kv)is runing for 2 hours with load of 900 amp and then it goes in shutdown with alarm fault messege of speed fault although heirtz reading fixed at 50,what does that mean
Civil Engineering (5086)
Mechanical Engineering (4456)
Electrical Engineering (16639)
Electronics Communications (3918)
Chemical Engineering (1095)
Aeronautical Engineering (239)
Bio Engineering (96)
Metallurgy (361)
Industrial Engineering (259)
Instrumentation (3014)
Automobile Engineering (332)
Mechatronics Engineering (97)
Marine Engineering (124)
Power Plant Engineering (172)
Textile Engineering (575)
Production Engineering (25)
Satellite Systems Engineering (106)
Engineering AllOther (1379)