Answer / mangesh

Fuse is healthy , 2.5 ohms thats means its shows continuity.

Answer / devi

yes,it is healthy.

Answer / samir

no it is unhealthy. Because it gives voltage drop between
the two ends.
In the circuit board this resistance of 2.5 Ohm is due to
the circuit other component. Actually fuse is generally
check by removing that fuse from the circuit board.
Ideally the fuse resistance is nearest to 0.

Answer / maddy

What is the output of Orifice plate, how can we check it is
ok or not.

can we create an interrupt in plc through scada?

0 Answers   Glensol, TATA,

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How signals can be taken through modbus?

1 Answers  

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䑰ҕ䔈ҕ䖠ҕ䘰ҕ䛀ҕ䝐ҕ䟐ҕ䢐ҕ䥐ҕŹ

0 Answers  

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diff bw range and span?

3 Answers  

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Specific gravity.

0 Answers   CCIE,

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if change the pid in D value so what action.

2 Answers   Siemens,

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IF TX SHOWS SLOW RESPONSE, WHILE A CLOSE LOOP AND WHEN WE PUT THE CONTROLLER ON MANUAL THE PROBLEM RECTIFIED, SO WE CAN SAY THE PROBLEM IS IN

1 Answers   IFFCO,

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ALL INSTRUMENTS WORKING PRINCIPLE.

3 Answers   Blanco, India Cements, TVS,

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I am applied 100 % pressure on to the air to open control valve,but the valve is not fully closed..and 10-15% is open the valve. how to calibrate the control valve?

3 Answers   OPaL,

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Can SmartPlant Instrumentation be used in a concurrent engineering environment?

1 Answers  

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Q1: Consider part of a control loop, which excludes the transmitter, consisting of a process, a controller and a control valve which may be represented by two dead times of 0.5 min each and three exponential lags of 0.8 min., 1.0 min. and 1.5 min. respectively. We wish to express this system as an overall first order plus dead time (FOPLD) model ie gain, time constant and process dead time. (We will see later that this is often done, to simplify controller tuning). For this exercise, gain is considered to be 1.0. (A) If the transmitter is a flow transmitter whose behaviour can be described by a dead time of 0.2 min. and an exponential lag of 0.5 min. in terms of the overall dead time and overall first order lag how can the system behaviour be approximated ? Overall dead time = Overall time constant = (B) If the transmitter is a temperature transmitter with a temperature sensor in a protecting well whose behaviour can be described by a dead time of 0.7 min. and an exponential lag of 15 min. how can the overall system behaviour be approximated now? Overall dead time = Overall time constant =

0 Answers  

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wht is loops ? how many loops are there?

2 Answers  

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