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how to convert decimal to binary in c using while loop
without using array
- 50 Answers
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Answer / prisonbreak
#include<conio.h>
#include<stdio.h>
main()
{
clrscr();
int a,b,c,d,e,f,g,h,num;
while(1)
{
printf("\t\t\t\nENTER THE NUMBER YOU WISH TO CONVERT\n");
scanf("%d",&num);
if(num<=255) /* 1 BYTE */
{
a=num%2;
b=(num/2)%2;
c=(num/4)%2;
d=(num/8)%2;
e=(num/16)%2;
f=(num/32)%2;
g=(num/64)%2;
h=num/128;
}
printf("\t\t\tTHE BINARY EQUIVALENT FOR %d IS
%d%d%d%d%d%d%d%d",num,h,g,f,e,d,c,b,a);
}
getche();
}
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / mushir
#include<stdio.h>
int main()
{
int n,a[100],i;
printf("Enter any no. :",n);
scanf("%d",&n);
while(n!=0)
{ for(i=0;i<=4;i++)
{
a[i]=n%2;
n=n/2;
}
}
for(i=4;i>=0;i--)
{
printf("%d",a[i]);
}
}
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / muhammad naeem mughal
The best answer to convert decimal to binary is
by Muhammad Naeem Mughal
University of Gujrat Pakistan
#include<iostream.h>
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int n,i,j,b[100];
cout<<"\n\t\tEnter decimal number: ";
cin>>n;
while (n>0)
{
b[i]=n%2;
n=n/2;
i++;
}
cout<<"\n\t\tBinary is: ";
j=i-1;
for (i=j;j>=0;j--)
{
cout<<b[j];
}
getch();
}
| Is This Answer Correct ? | 4 Yes | 6 No |
Answer / jimmy
#include<stdio.h>
#include<conio.h>
void covert2binary(int);
void main()
{
int num;
clrscr();
printf("enter numer: ");
scanf("%d:",&num);
covert2binary(num);
getch();
}
void covert2binary(int n)
{
int i=0,j,b[100];
while (n>0)
{
b[i]=n%2;
n=n/2;
i++;
}
printf("\nBinary is: ");
j=i-1;
for (i=j;j>=0;j--)
{
printf("%d", b[j]);
}
}
| Is This Answer Correct ? | 5 Yes | 8 No |
Answer / nirav panchal
#include<stdio.h>
#include<conio.h>
void main()
{
int dec,i=1,rem,res=0;
clrscr();
printf("Enter the Value");
scanf("%d",&dec);
while(dec>0)
{
rem=dec%2;
dec=dec/2;
res=res+(i * rem);
i=i*10;
}
printf("The Binary value is %d",res);
getch();
}
| Is This Answer Correct ? | 5 Yes | 8 No |
Answer / aya mohamed
#include<iostream>
using namespace std;
int main()
{
int dec,rem,i=1;
long int bin=0;
printf("Enter the decimal number : ");
scanf("%d",&dec);
while(dec>0)
{
rem=dec%2;
dec=dec/2;
bin=bin+(i*rem);
i=i*10;
}
printf("The binary number is %l",bin);
getch();
}
//main fun must return int number
| Is This Answer Correct ? | 2 Yes | 6 No |
Answer / bhavin tank
//decimal to binary using for and array
#include<iostream.h>
#include<conio.h>
void conv(int n)
{
int a[100],i;
for(i=0;n!=0;i++)
{
a[i]=n%2;
n=n/2;
}
cout<<"the binary is";
for(i-=1;i>=0;i--)
{
cout<<a[i];
}
}
void main()
{
clrscr();
int n;
cout<<"enter the no:";
cin>>n;
conv(n);
getch();
}
| Is This Answer Correct ? | 5 Yes | 10 No |
#include <iostream.h>
#include <conio.h>
#include <stdlib.h>
void main()
{
int i=23;
char c[23];
clrscr();
cout<<"Enter any Number in Decimal to be converted in Binary\n";
cin>>i;
cout<<itoa(i,c,2);
getch();
}
| Is This Answer Correct ? | 9 Yes | 15 No |
Answer / daryl
int main()
{
int a = 0,r[10],dec,quo;
clrscr();
printf("Enter Decimal number: ");
scanf("%i",&quo);
while(quo>0)
{
r[a]=quo%2;
quo=quo/2;
a++;
}
a=a-1;
while(a>=0)
{
printf("%i",r[a]);
a--;
}
getch();
return(0);
}
| Is This Answer Correct ? | 8 Yes | 19 No |
void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?
What is the out put of this programme? int a,b,c,d; printf("Enter Number!\n"); scanf("%d",&a); while(a=!0) { printf("Enter numbers/n"); scanf("%d%d%d",&b,&c,&d); a=a*b*c*d; } printf("thanks!"); getche(); Entering numbers are a=1,b=2,c=3,d=4 b=3,c=4,d=-5 b=3,c=4,d=0
void main() { int i=5,y=3,z=2,ans; clrscr(); printf("%d",++i + --z + i++ + --i * ++y); i=5,y=3,z=2; ans=++i + --z + i++ + --i * ++y; printf("\n%d",ans); getch(); } Its output is 37 and 31.... Please explain me why its different How it works.....
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void main() { int i=5; printf("%d",i+++++i); }
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