Answer / nimesh soni

#include<stdio.h>
#include<conio.h>
void main()
{
long int no;
long int i,k,andmask;
clrscr();
printf("No : ");
scanf("%ld",&no);
printf("\n");
for(i=20;i>=0;i--)
{
andmask=1<<i;
k=no & andmask;
k==0?printf("0 "):printf("1 ");
}
getch();
}

Answer / kishore

void main()
{
int dec,rem,k=1;
long int bin=0;
printf("Enter the decimal number : ");
scanf("%d",&dec);
while(dec>0)
{
rem=dec%2;
dec=dec/2;
bin=bin+(k*rem);
k=k*10;
}
printf("The binary number is %l",bin);
getch();
}

Answer / rudresh

#include<iostream>
#include <conio.h>
#include<vector>

using namespace std;
// Create a function to return the n to the power of m
// or you can you pow() of <math.h> but you will have to //use the casting.

int pow(int n ,int m)
{
int ans = 1;
for(int i =1 ;i<= m;i++)
ans = n*ans;
return ans;
}


vector<int> binary(int a){
vector<int> v;

while(a != 0){

v.push_back(a%2);
a/=2;
}
return v;
}
int main(){
int decno ,binno = 0 ;
cout<<"Enter no to get binary:- ";
cin>>decno;
vector<int> v;
v = binary(decno);

while(!v.empty())
{
binno = binno + v.back()*pow(10,v.size()- 1);
v.pop_back();
}

cout<< binno;

_getch();
return 0;
}

Answer / somya garg

#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c;
long ans=1;
clrscr();
printf("enter value in decimal=");
scanf("%d",&a);
c=a;
if(a%2==0||a==1)
a=a;
else
a=a-1;
while(a>1)
{
b=a%2;
a=a/2;
ans=ans*10+b;
}
if(c%2==0||c==1)
printf("ans in binary=%ld",ans);
else
printf("ans in binary=%ld",ans+1);
getch();
}

Answer / chiran ravani

#include <stdio.h>
void main()
{
int n, r, i=0, j, a[10], k=0;
clrscr();
printf("Enter decimal number (upto 1024):");
scanf("%d",&n);
j = n;
do
{
r = n%2;
n = n/2;
a[k] = r;
k++;
i = (i*10) + r;
}while(n>0);
printf("\nBinary equivalent of %d = ",j);
for(j=k-1;j>=0;j--)
{
printf("%d",a[j]);
}
getch();
}

Answer / anubhab pal

@#include<stdio.h>
void main()
{
int decimal,r,binary=0,i=1;
printf("Eneter a Decimal Number: ");
scanf("%d",&decimal);
while(decimal!=0)
{
r=decimal%2;
decimal=decimal/2;
binary=binary+(i*r);
i=i*10;
}
printf("\nThe binary number is: %d\n",bin);
}

Answer / raj bahadur patel

#include<stdio.h>
#include<conio.h>
void func(int ,int );
void main()
{
int ch,dec;

clrscr();
printf("Enter the number\n");
scanf("%d",&dec);
printf("Enter 1. for decimal to binary ");
printf("Enter 2. for decimal to octal ");
printf("Enter 3.to exit ");
printf("enter ur choice");
scanf("%d",&ch);
switch(ch)
{
case 1:
printf("Binary equivalent is :");
func(dec,2);
break;
case 2:
printf("octal equivalent is :");
func(dec,8);
break;

default:
printf("Wrong choice ");
}

getch();
}

void func(int dec,int b)
{
int i=0,j=0;
int r,ch;
int p[10];
while(dec>0)
{
p[i]=0;
r=dec%b;
dec=dec/b;
p[i]=r;
i++;
}
printf("The binary number is...\n");

for(j=i-1;j>=0;j--)
printf("%d",p[j]);
}

Answer / preeti bahuguna

#include<stdio.h>
#include<conio.h>
void main()
{
int dec,rem,i=1;
long int bin=0;
printf("Enter the decimal number : ");
scanf("%d",&dec);
while(dec>0)
{
rem=dec%2;
dec=dec/2;
bin=bin+(i*rem);
i=i*10;
}
printf("The binary number is %ld",bin);
getch();
}

Answer / ankita batt

#include<stdio.h>
#include<conio.h>
void main()
{
int n=0,i=0;
int a[31];
clrscr();
printf("\nenter the number \n");
scanf("%d",&n);
do
{
for(i=0;i<32;i++)
{
a[i]=n%2;
n=n/2;
}
}while((n%2)!=0);
for(i=31;i>=0;i--)
{
printf("%2d",a[i]);
}
getch();
}

Answer / amir

#include<conio.h>
#include<stdio.h>

main()
{
clrscr();
int a,b,c,d,e,f,g,h,num;
while(1)
{
printf("\t\t\t\nENTER THE NUMBER YOU WISH TO CONVERT\n");
scanf("%d",&num);
if(num<=255) /* 1 BYTE */
{
a=num%2;
b=(num/2)%2;
c=(num/4)%2;
d=(num/8)%2;
e=(num/16)%2;
f=(num/32)%2;
g=(num/64)%2;
h=num/128;
}
printf("\t\t\tTHE BINARY EQUIVALENT FOR %d IS
%d%d%d%d%d%d%d%d",num,h,g,f,e,d,c,b,a);
}
getche();
}

I'm having trouble with coming up with the correct code. Thank You!! The assignment was to write a program using string functions that accepts a price of an item and displays its coded value. The base of the keys: X C O M P U T E R S 0 1 2 3 4 5 6 7 8 9 Sample I/O Dialogue: Enter Price: 489.50 Coded Value: PRS.UX

0 Answers  

What is the out put of this programme? int a,b,c,d; printf("Enter Number!\n"); scanf("%d",&a); while(a=!0) { printf("Enter numbers/n"); scanf("%d%d%d",&b,&c,&d); a=a*b*c*d; } printf("thanks!"); getche(); Entering numbers are a=1,b=2,c=3,d=4 b=3,c=4,d=-5 b=3,c=4,d=0

5 Answers   TCS,

How to convert hexadecimal to binary using c language..

1 Answers   Bajaj, GAIL, Satyam, Zenqa,

Given that two int variables, total and amount , have been declared, write a sequence of statements that: initializes total to 0 reads three values into amount , one at a time. After each value is read in to amount , it is added to the value in total (that is, total is incremented by the value in amount ). Instructor's notes: If you use a loop, it must be a for loop. And if you use a loop control variable for counting, you must declare it.

1 Answers   Google,

#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }

1 Answers  

What is the code for following o/p * * * * * * * * * * * * * * * *

1 Answers  

void main() { int i=5,y=3,z=2,ans; clrscr(); printf("%d",++i + --z + i++ + --i * ++y); i=5,y=3,z=2; ans=++i + --z + i++ + --i * ++y; printf("\n%d",ans); getch(); } Its output is 37 and 31.... Please explain me why its different How it works.....

2 Answers  

I am using Qt 5.6 during compilation it stops and gives error about Qmake The process "C:QtQt5.6.35.6.3msvc2015_64inqmake.exe" crashed. Error while building/deploying project untitled1 (kit: Desktop Qt 5.6.3 MSVC2015 64bit) When executing step "qmake"

0 Answers  

how to convert decimal to hexadecimal without using arrays just loops

2 Answers  

Write a C program to enter 10 integer numbers through one variable and count how many of them are even using while loop ?

2 Answers  

when i use cout or cin call & then either << or >> .....it shows declaration syntax error...what should i do? cout<<"anything"; int a; cin>>a; return 0;

2 Answers  

How to develop a program using C language to convert 8-bit binary values to decimals. TQ

1 Answers   Amazon,