Answer / tushar srivastava

Hello Friends,
I am having a question here....
If you can save a binary number in at maximum four bytes,
then why are you wasting 16 bytes for the same. This method
is not recommended by me lest you need to send data to some
output port. And even the previous method ie my method can
directly be used to transfer data though serial or parallel
port if needed. Ponder over it......

Answer / praveenkumar

#include<stdio.h>
#include<conio.h>
void main()
{
long int dec,k=0,i=0,j=0,n,remainder,result[100];
printf("\n Enter any Value : ");
scanf("%ld",&dec);
while(dec>0)
{
remainder=dec%2;
result[k]=remainder;
k++;
dec=dec/2;
if(remainder==0)
{
i++;
}
else
{
j++;
}
}
printf("\n Binary : ");
for(n=k-1;n>=0;n--)
printf("%d",result[n]);
printf("\n 0's : %ld",i);
printf("\n 1's : %ld",j);
printf("\n Total Digits : %d",k);
getch();
}

Answer / suresh

#include<stdio.h>
#include<conio.h>
void main()
{
int i,n;
clrscr();
scanf("%d",&n);
i=0;
while(i<=15)
{
printf("%d",(n<<i)&(1<<15)?1:0);
i++;
}
}

Answer / bhagyashree

Q.How to convert to binary to decimal in c++ using array.

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int i,n,j[8]={1,2,4,8,16,32},k=0;
int num[10],num1[10],s=0;
cout<<"Enter total num of digit:";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"\nEnter "<<i+1<<" position";
cin>>num[i];
}
for(i=n-1;i>=0;i--)
{
num1[i]=num[i]*j[k];
s=s+num1[i];
k++;
}
cout<<"s="<<s;
getch();
}

Answer / deva

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
long int bn,temp;
int dn=0,e=0,digit;
clrscr();
printf("Enter binary number in form of 0 and 1 : ");
scanf("%ld",&bn);
temp=bn;
while(bn!=0)
{
digit= bn%10;
dn+=digit*pow(2,e);
e++;
bn/=10;}
printf("Binary number = %ld \n",temp);
printf("Decimal number= %d \n",dn);
getch();}

Answer / chiran ravani

#include<stdio.h>
int main(void) {
int n,i=7,bin;
printf("Enter a decimal no:");
scanf("%d",&n);
while(i>=0) {
bin=n>>i;
if(bin&1)
printf("1");
else
printf("0");
i--;
}
}

Answer / chiran ravani

sorry friends please ignore the previous answer.

Answer / zahid

Any body help me to write a program to convert decimal to binary without using loop

Answer / govind kumar

#include<conio.h>
#include<stdio.h>
void main()
{
int n,b=0,d=1,r,i=1;
printf("enter any binary no");
scanf("%d",&b);
while(n>0)
{
r=n%2;
b=b+r*d;
d=d*10;
n=n/2;
}
printf("the binary no is=%d",b);
}
getch;
}

Answer / purva

#include<stdio.h>
#include<conio.h>
void main()
{
int n,i=1,a,d=0,b=0,c;
clrscr();
printf("enter decimal no.");
scanf("%d",&n);
while(n!=0)
{
a=n%2;
n=n/2;
d=d*10+a;
i++;
}
printf("d=%d",d);
while(d!=0)
{
c=d%10;
d=d/10;
b=b*10+c;
i++;
}
printf("\n binary equivalent is=%d",b);
getch();
}

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6 Answers   HCL,

#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }

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