How to convert hexadecimal to binary using c language..
Answer / nipun
#include <stdio.h>
#include <math.h>
#include <string.h>
void binary_hex(int n, char hex[]);
int hex_binary(char hex[]);
int main()
{
char hex[20],c;
int n;
printf("\nInstructions:\n");
printf("Enter h to convert binary to hexadecimal:\n");
printf("Enter b to hexadecimal number to binary:\n");
printf("Enter a character: ");
scanf("%c",&c);
if (c=='h' || c=='H')
{
printf("Enter binary number: ");
scanf("%d",&n);
binary_hex(n,hex);
printf("Hexadecimal number: %s",hex);
}
if (c=='b' || c=='B')
{
printf("Enter hexadecimal number: ");
scanf("%s",hex);
printf("Binary number: %d",hex_binary(hex));
}
return 0;
}
void binary_hex(int n, char hex[]) /* Function to convert
binary to hexadecimal. */
{
int i=0,decimal=0, rem;
while (n!=0)
{
decimal += (n%10)*pow(2,i);
n/=10;
++i;
}
/* At this point, variable decimal contains binary number in
decimal format. */
i=0;
while (decimal!=0)
{
rem=decimal%16;
switch(rem)
{
case 10:
hex[i]='A';
break;
case 11:
hex[i]='B';
break;
case 12:
hex[i]='C';
break;
case 13:
hex[i]='D';
break;
case 14:
hex[i]='E';
break;
case 15:
hex[i]='F';
break;
default:
hex[i]=rem+'0';
break;
}
++i;
decimal/=16;
}
hex[i]='\0';
strrev(hex); /* Function to reverse string. */
}
int hex_binary(char hex[]) /* Function to convert
hexadecimal to binary. */
{
int i, length, decimal=0, binary=0;
for(length=0; hex[length]!='\0'; ++length);
for(i=0; hex[i]!='\0'; ++i, --length)
{
if(hex[i]>='0' && hex[i]<='9')
decimal+=(hex[i]-'0')*pow(16,length-1);
if(hex[i]>='A' && hex[i]<='F')
decimal+=(hex[i]-55)*pow(16,length-1);
if(hex[i]>='a' && hex[i]<='f')
decimal+=(hex[i]-87)*pow(16,length-1);
}
/* At this point, variable decimal contains the hexadecimal
number in decimal format. */
i=1;
while (decimal!=0)
{
binary+=(decimal%2)*i;
decimal/=2;
i*=10;
}
return binary;
}
Is This Answer Correct ? | 0 Yes | 0 No |
Write a c-programe that input one number of four digits and find digits sum?
what is exceptions?
void main() { int i=5; printf("%d",i+++++i); }
#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }
Declaration of Cube Guys please help me.. Is this a right way to declare cube.? If i Compile it. It Says: Cube undeclared what should i do? Please help \thanks in advanced #include<stdio.h> #include<math.h> #include<conio.h> main( ) { float x,y; while(x++<10.0) { printf("Enter Number:"); scanf("%d", &x); y = cube(x); printf("%f %f %f \n", x,pow(x,2),y); cube(x); } { float x; float y; y = x*x*x; } getch(); return (y); }
what is syntax error?
how tally is useful?
write the value of x and y after execution of the statements: int x=19,y; y=x++ + ++x; x++; y++;
How to convert hexadecimal to binary using c language..
1 Answers Bajaj, GAIL, Satyam, Zenqa,
Answering Yes or No in C++...using only stdio.h and conio.h..........help me please...? here's must be the output of the program: Screen A Exam No. items Score 1 20 20 2 35 35 Another Entry? [Y] or [N] : Screen B: Record No. Student's Name: 1 Fernando Torres 2 Chuck Norris Note: if you press Y, the program must repeat the procedure in screen A, then if N, the program must proceed to the screen B....Please Help me out............
Write a program to accept two strings of Odd lengths. Then take all odd characters from one string and even characters from the other and concatenate and produce a string.
what are the techniques for reducing the fragility of a memory bug?