Answer / nipun

#include <stdio.h>
#include <math.h>
#include <string.h>
void binary_hex(int n, char hex[]);
int hex_binary(char hex[]);
int main()
{
char hex[20],c;
int n;
printf("\nInstructions:\n");
printf("Enter h to convert binary to hexadecimal:\n");
printf("Enter b to hexadecimal number to binary:\n");
printf("Enter a character: ");
scanf("%c",&c);
if (c=='h' || c=='H')
{
printf("Enter binary number: ");
scanf("%d",&n);
binary_hex(n,hex);
printf("Hexadecimal number: %s",hex);
}
if (c=='b' || c=='B')
{
printf("Enter hexadecimal number: ");
scanf("%s",hex);
printf("Binary number: %d",hex_binary(hex));
}
return 0;
}

void binary_hex(int n, char hex[]) /* Function to convert
binary to hexadecimal. */
{
int i=0,decimal=0, rem;
while (n!=0)
{
decimal += (n%10)*pow(2,i);
n/=10;
++i;
}

/* At this point, variable decimal contains binary number in
decimal format. */
i=0;
while (decimal!=0)
{
rem=decimal%16;
switch(rem)
{
case 10:
hex[i]='A';
break;
case 11:
hex[i]='B';
break;
case 12:
hex[i]='C';
break;
case 13:
hex[i]='D';
break;
case 14:
hex[i]='E';
break;
case 15:
hex[i]='F';
break;
default:
hex[i]=rem+'0';
break;
}
++i;
decimal/=16;
}
hex[i]='\0';
strrev(hex); /* Function to reverse string. */
}

int hex_binary(char hex[]) /* Function to convert
hexadecimal to binary. */
{
int i, length, decimal=0, binary=0;
for(length=0; hex[length]!='\0'; ++length);
for(i=0; hex[i]!='\0'; ++i, --length)
{
if(hex[i]>='0' && hex[i]<='9')
decimal+=(hex[i]-'0')*pow(16,length-1);
if(hex[i]>='A' && hex[i]<='F')
decimal+=(hex[i]-55)*pow(16,length-1);
if(hex[i]>='a' && hex[i]<='f')
decimal+=(hex[i]-87)*pow(16,length-1);
}
/* At this point, variable decimal contains the hexadecimal
number in decimal format. */

i=1;
while (decimal!=0)
{
binary+=(decimal%2)*i;
decimal/=2;
i*=10;
}
return binary;
}

errors are known as?

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