Answer / pushkar kalantri

#include<stdio.h>
#include<string.h>

void main()
{
char
v1[11]={'X','C','O','M','P','U','T','E','R','S','\0'},p='.';
int v2[11]={0,1,2,3,4,5,6,7,8,9};
char ip[10];
int n,i,j,k=0,cnt=0;
//clrscr();

printf("Enter coded value: ");
scanf("%s",ip);

// printf("\nur entered code = %s",ip);
printf("\nUr price is = ");


for(i=0;v1[i]!='\0';i++)
{
if(ip[k]=='.')
{
++k;
printf("%c",p);
}
if(ip[k]==v1[i])
{
printf("%d",i);
++k;
i=-1;
if(ip[k]=='\0')
break;
}
}
}
//compiled by GCC

Answer / levixnu

#include<stdio.h>
#include<string.h>
#include<conio.h>

void main()
{
char
v1[11]={'X','C','O','M','P','U','T','E','R','S','\0'},p='.';
int v2[11]={0,1,2,3,4,5,6,7,8,9};
char ip[10];
int n,i,j,k=0,cnt=0;
clrscr();

printf("Enter coded value: ");
scanf("%s",ip);

printf("\nur entered code = %s",ip);
printf("\nUr price is = ");


for(i=0;v1[i]!='\0';i++)
{
if(ip[k]=='.')
{
++k;
printf("%c",p);
}
if(ip[k]==v1[i])
{
printf("%d",i);
++k;
i=-1;
if(ip[k]=='\0')
break;
}
}
getch();
}

Answer / roxy

#include<stdio.h>
#include<string.h>

main()
{
char v1[11]={'X','C','O','M','P','U','T','E','R','S','\0'};
char v2[11]={'0','1','2','3','4','5','6','7','8','9','\0'};

int n;
clrscr();

printf("Enter coded value: ");
scanf("%s",v1);

n=strncpy(v1, v2, 1);

v2[1]='\0';

printf("\nTag Price: %s ",v2);

getch();
}

who was the present cheif governor of reserve bank of india

6 Answers   State Bank Of India SBI,

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class test { int a; public: test(int b):a(b){} void show(){ cout<<a; } }; void main() { test t1; test t2(5); t1.show(); t2.show(); } }

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what is meant for variable not found?

3 Answers  

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Using string functions write a program that will accept the name of the capital as input value and will display the corresponding country. ------------------------ Capitals Countries ------------------------ Capitals Countries Ottawa Canada Moscow Russia Rome Italy I can't not get it to run properly

1 Answers   AMA,

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wap for bubble sort

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Write a c-programe that input one number of four digits and find digits sum?

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when i use cout or cin call & then either << or >> .....it shows declaration syntax error...what should i do? cout<<"anything"; int a; cin>>a; return 0;

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What is probability to guarantee that the task a programmer is going to create will be created and be able to run on a particular system (RTOS/GPOS).

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Find the error (2.5*2=5) (a) X=y=z=0.5,2.0-5.75 (b) s=15;

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Given an int variable n that has already been declared and initialized to a positive value, and another int variable j that has already been declared, use a do...while loop to print a single line consisting of n asterisks. Thus if n contains 5, five asterisks will be printed. Use no variables other than n and j .

2 Answers  

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#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }

1 Answers  

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Declaration of Cube Guys please help me.. Is this a right way to declare cube.? If i Compile it. It Says: Cube undeclared what should i do? Please help \thanks in advanced #include<stdio.h> #include<math.h> #include<conio.h> main( ) { float x,y; while(x++<10.0) { printf("Enter Number:"); scanf("%d", &x); y = cube(x); printf("%f %f %f \n", x,pow(x,2),y); cube(x); } { float x; float y; y = x*x*x; } getch(); return (y); }

2 Answers  

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