Answer / dhananjay

#include<stdio.h>
#include<conio.h>
#include<math.h>
#include<process.h>
void main()
{
float a,b,c,x1,x2,disc;
clrscr();
printf("Enter the co-efficients\n");
scanf("%f%f%f",&a,&b,&c);
disc=b*b-4*a*c;/*to find discriminant*/
if(disc>0)/*distinct roots*/
{
x1=(-b+sqrt(disc))/(2*a);
x2=(-b-sqrt(disc))/(2*a);
printf("The roots are distinct\n");
exit(0);
}
if(disc==0)/*Equal roots*/
{
x1=x2=-b/(2*a);
printf("The roots are equal\n");
printf("x1=%f\nx2=%f\n",x1,x2);
exit(0);
}
x1=-b/(2*a);/*complex roots*/
x2=sqrt(fabs(disc))/(2*a);
printf("The roots are complex\n");
printf("The first root=%f+i%f\n",x1,x2);
printf("The second root=%f-i%f\n",x1,x2);
getch();
}

Answer / pratibha

//program to find roots of given equation
#include<stdio.h>
#include<math.h>
void main()
{
int a,b,c;
float d,p,q,r,s;
printf("\n\n Enter the values of a,b,c")
scanf("%d%d%d",&a,&b,&c);
d=(b*b)-(4*a*c);
if(d=0)
{
printf("\n The roots are real and equal");
p=(-b)/(2*a);
q=(-b)/(2*a);
printf("\n The roots of the equation are %f,%f",p,q);
}
if(d>0)
{
printf("\n The roots are real and distinct");
p=((-b)+sqrt((b*b)-(4*a*c)))/(2*a);
q=((-b)-sqrt((b*b)-(4*a*c)))/(2*a);
printf("\n The roots of the equation are %f,%f",p,q);
}
if(d<0)
{
printf("\n The roots are imaginary");
r=(-b)/(2*a);
s=(sqrt((4*a*c)-(b*b)))/(2*a);
printf("\n The roots of the equation are
p=%f=%fi,q=%f-%fi",r,s,r,s);
}
}

Answer / pankaj

Lets i see first

Answer / vikas tiwari

#include <iostream.h>
#include <conio.h>
#include <math.h>
int main()
{
clrscr();
float a,b,c,d,root1,root2;
cout << "Enter the 3 coefficients a, b, c : " << endl;
cin>>a>>b>>c;
if(!a){
if(!b)
cout << "Both a and b cannot be 0 in ax^2 + bx + c = 0" << "\n";
else
{
d=-c/b;
cout << "The solution of the linear equation is : " << d << endl;
}
}
else
{
d=b*b-4*a*c;
if(d>0)
root1=(-b+sqrt(d))/(2*a);
root2=(-b-sqrt(d))/(2*a);
cout << "The first root = " << root1 << endl;
cout << "The second root = " << root2 << endl;
}
getch();
return 0;
}

Answer / lady k

#include<stdio.h>
#include<conio.h>
#include<math.h>
#include<stdlib.h>
int main ()
{
/*Main: Solve the quadratic equation*/
float r, a, b, c, x1, x2, d;
printf ("Enter the value of a: ");
scanf ("%f", &a);
printf ("\nEnter the value of b: ");
scanf ("%f", &b);
printf ("\nEnter the value of c: ");
scanf ("%f", &c);
printf("\n");
d= b*b-4*a*c;
r= sqrt(d);
x1= (-b + r)/(2*a);
x2=(-b- r)/(2*a);
if (d>0)
{
printf ("The real roots of the equation are %f",
x1);
printf (" and %f", x2);
}
else if (x1==x2)
{
x1= (-b+r)/(2*a);
printf ("x1 and x2 are equal roots %f", x1);
}
else if (a<0)
{
x1= (-b + r)/(2*a);
x2=(-b- r)/(2*a);
printf ("The roots of the equation are %f", x1);
printf (" and %f", x2);
}
else
printf ("The roots of the equation are
complex");
getch ();
return 0;
}

Answer / bawaaaa

//program to find roots of given equation
#include<stdio.h>
#include<math.h>
void main()
{
int a,b,c;
float d,p,q,r,s;
printf("\n\n Enter the values of a,b,c")
scanf("%d%d%d",&a,&b,&c);
d=(b*b)-(4*a*c);
if(d=0)
{
printf("\n The roots are real and equal");
p=(-b)/(2*a);
q=(-b)/(2*a);
printf("\n The roots of the equation are %f,%f",p,q);
}
if(d>0)
{
printf("\n The roots are real and distinct");
p=((-b)+sqrt((b*b)-(4*a*c)))/(2*a);
q=((-b)-sqrt((b*b)-(4*a*c)))/(2*a);
printf("\n The roots of the equation are %f,%f",p,q);
}
if(d<0)
{
printf("\n The roots are imaginary");
r=(-b)/(2*a);
s=(sqrt((4*a*c)-(b*b)))/(2*a);
printf("\n The roots of the equation are
p=%f=%fi,q=%f-%fi",r,s,r,s);
}
}

Answer / asif ahmed

/* PROGRAM TO FIND THE ROOTS OF A QUADRATIC EQUATION WITH
APPROPRIATE ERROR MESSAGE */

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
float a,b,c,disc,root1,root2,part_r,part_i;
int flag;
clrscr();
printf("Enter the coefficients of quadratic equation \n");
scanf("%f%f%f",&a,&b,&c);
printf("coefficients are a=%f\t b=%f\t c=%f\n",a,b,c);
if((a==0)||(b==0)||(c==0))
printf("\nZero coefficeints");
else
{
disc=(b*b)-(4*a*c);
if(disc==0)
flag=0;
if(disc>0)
flag=1;
if(disc<0)
flag=2;
switch(flag)
{
case0 : printf("\n Roots are real and equal");
root1=-(-b)/(2*a);
root2=root1;
printf("\n root1=%f",root1);
printf("\n root2=%f",root2);
break;
case1 : printf("\n Roots are real and distinct");
root1=(-b+sqrt(disc))/(2*a);
root2=(-b-sqrt(disc))/(2*a);
printf("\n root1=%f",root1);
printf("\n root2=%f",root2);
break;
case2 : printf("\n Roots are real and Imaginary");
part_r=(-b)/(2*a);
part_i=(sqrt(-disc))/(2.0*a);
printf("\n root1=%f +i%f",part_r,part_i);
printf("\n root2=%f -i%f",part_r,part_i);
break;
}
}
getch();
}

Answer / rupamjit

//program to find roots of given equation
#include<stdio.h>
#include<math.h>
void main()
{
int a,b,c;
float d,p,q,r,s;
printf("\n\n Enter the values of a,b,c=");
scanf("%d%d%d",&a,&b,&c);
d=(b*b)-(4*a*c);
if(d==0)
{
printf("\n The roots are real and equal.");
p=(-b)/(2*a);
q=(-b)/(2*a);
printf("\n The roots of the equation are %.0fand%.0f",p,q);
}
if(d>0)
{
printf("\n The roots are real and distinct");
p=((-b)+sqrt((b*b)-(4*a*c)))/(2*a);
q=((-b)-sqrt((b*b)-(4*a*c)))/(2*a);
printf("\n The roots of the equation are %.0fand%.0f",p,q);
}
if(d<0)
{
printf("\n The roots are imaginary");
r=(-b)/(2*a);
s=(sqrt((4*a*c)-(b*b)))/(2*a);
printf("\n The roots of the equation arep=%.2f=%.2fi,q=%.2f-%.2fi",r,s,r,s);
}
getch();
}

Answer / jijo alexander

#include<stdio.h>
void main()
{
int a,b,c;
float d,r1,r2;

printf("\n\n\t\tSolving the quadratic equation");
printf("\n\t\t********************************");


printf("\n\n\tEnter The Coefficent");
printf("\n\t======================");


/*Out put screen */

printf("\n\tCoefficent Of 'X^2' : ");
scanf(%d",&a);

printf("\n\tCoefficent Of 'X' : ");
scanf("%d",&b);

printf("\n\tConstant Value : ");
scanf("%d",&c);

d=(b*b)-(4*a*c);

if(d<0)
printf('\n\n\tImaginary Roots ");
else if(d==0)
{
r1=(-b)*(2*a);
printf("\n\tEqual Roots");
}
else
{
printf("\n\tReal roots : ");
r1=(-b+sqrt(d))/(2*a);
r2=(-b-sqrt(d))/(2*a);
printf("\t %g , %g",r1,r2);
}
getch();
}

Answer / sachin kumar

#include<stdio.h>
int main()
{
int a,b,c,r1,r2,disc;
printf("Enter the number of a,b,c:");
scanf("%d\n%d\n%d",&a,&b,&c);
disc= b*b-4*a*c;
if(disc<0)
{
printf("Roots are imaginary");
}
else if(disc==0)
{
r1=(-b)/a;
r2=r1;
printf("The Root1 and Root2 are equal and roots are
%d\n,%d",r1,r2);
}
else
{
r1=(-b+((b*b)-4*a*c))/2*a;
r2=(-b-((b*b)-4*a*c))/2*a;
printf("The Root1 and Root2 are %d\n,%d\n",r1,r2);
}
}

There is a lucky draw held every day. if there is a winning number eg 1876,then all possible numbers like 1867,1687,1768 etc are the numbers that match irrespective of the position of the digit. Thus all these numbers qualify fr the lucky draw prize Assume there is no zero digit in any numbers. write a program to show all the possible winning numbers if a "winning number"is passed as an arguments to the function.

1 Answers   Nagarro,

3) Int Matrix of certain size was given, We had few valu= es in it like this. =97=97=97=97=97=97=97=97=97=97=97 1 = | 4 | | 5 | &= nbsp; | 45 =97=97=97=97=97=97=97=97=97=97=97 &n= bsp; | 3 | 3 | 5 | = | 4 =97=97=97=97=97=97=97=97=97=97=97 34 |&nbs= p; 3 | 3 | | 12 | &= nbsp; =97=97=97=97=97=97=97=97=97=97=97 3 | &nbs= p; | 3 | 4 | = | 3 =97=97=97=97=97=97=97=97=97=97=97 3 | = ; | | | = ; 3 | =97=97=97=97=97=97=97=97=97=97=97 &= nbsp; | | 4 | = ; | 4 | 3 We w= ere supposed to move back all the spaces in it at the end. Note: = If implemented this prog using recursion, would get higher preference.

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