void main()
{
static int i=5;
if(--i){
main();
printf("%d ",i);
}
}
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Answer / susie
Answer :
0 0 0 0
Explanation:
The variable "I" is declared as static, hence memory for I
will be allocated for only once, as it encounters the
statement. The function main() will be called recursively
unless I becomes equal to 0, and since main() is recursively
called, so the value of static I ie., 0 will be printed
every time the control is returned.
| Is This Answer Correct ? | 4 Yes | 5 No |
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