Answer / susie

Answer :

0 0 0 0

Explanation:

The variable "I" is declared as static, hence memory for I
will be allocated for only once, as it encounters the
statement. The function main() will be called recursively
unless I becomes equal to 0, and since main() is recursively
called, so the value of static I ie., 0 will be printed
every time the control is returned.

Give a one-line C expression to test whether a number is a power of 2.

10 Answers   Microsoft,

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main() { int i; clrscr(); for(i=0;i<5;i++) { printf("%d\n", 1L << i); } } a. 5, 4, 3, 2, 1 b. 0, 1, 2, 3, 4 c. 0, 1, 2, 4, 8 d. 1, 2, 4, 8, 16

4 Answers   HCL,

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main() { char *p = "hello world"; p[0] = 'H'; printf("%s", p); } a. Runtime error. b. “Hello world” c. Compile error d. “hello world”

5 Answers   HCL,

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main() { int i=3; switch(i) { default:printf("zero"); case 1: printf("one"); break; case 2:printf("two"); break; case 3: printf("three"); break; } }

1 Answers  

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given integer number,write a program that displays the number as follows: First line :all digits second line : all except the first digit . . . . Last line : the last digit

8 Answers  

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Write out a function that prints out all the permutations of a string. For example, abc would give you abc, acb, bac, bca, cab, cba. You can assume that all the characters will be unique.

5 Answers   IITR, Microsoft, Nike,

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#define assert(cond) if(!(cond)) \ (fprintf(stderr, "assertion failed: %s, file %s, line %d \n",#cond,\ __FILE__,__LINE__), abort()) void main() { int i = 10; if(i==0) assert(i < 100); else printf("This statement becomes else for if in assert macro"); }

1 Answers  

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All the combinations of prime numbers whose sum gives 32

1 Answers   HHH,

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#define a 10 void foo() { #undef a #define a 50 } int main() { printf("%d..",a); foo(); printf("%d..",a); return 0; } explain the answer

1 Answers  

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#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d..%d",*p,*q); }

1 Answers  

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main() { int x=5; clrscr(); for(;x<= 0;x--) { printf("x=%d ", x--); } } a. 5, 3, 1 b. 5, 2, 1, c. 5, 3, 1, -1, 3 d. –3, -1, 1, 3, 5

2 Answers   HCL,

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There were 10 records stored in “somefile.dat” but the following program printed 11 names. What went wrong? void main() { struct student { char name[30], rollno[6]; }stud; FILE *fp = fopen(“somefile.dat”,”r”); while(!feof(fp)) { fread(&stud, sizeof(stud), 1 , fp); puts(stud.name); } }

1 Answers  

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