how can i cast a char type array to an int type array
Answers were Sorted based on User's Feedback
Answer / moolshankershukla
int a[10];
char b[10];
a[10]=(char) b[10]; // type casting char type into int type.
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / harish
int b[10];char a[10];
for(int i=0;i<10;i++)
b[i]=(int)a[i];
| Is This Answer Correct ? | 1 Yes | 0 No |
int i=10; main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); }
Write a program that produces these three columns sequence nos. using loop statement Sequence nos. Squared Squared + 5 1 1 6 2 4 9 3 9 14 4 16 21 5 25 30
struct Foo { char *pName; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); strcpy(obj->pName,"Your Name"); printf("%s", obj->pName); } a. Your Name b. compile error c. Name d. Runtime error
main() { char *p = “ayqm”; char c; c = ++*p++; printf(“%c”,c); }
void main() { int i=5; printf("%d",i+++++i); }
union u { union u { int i; int j; }a[10]; int b[10]; }u; main() { printf("\n%d", sizeof(u)); printf(" %d", sizeof(u.a)); // printf("%d", sizeof(u.a[4].i)); } a. 4, 4, 4 b. 40, 4, 4 c. 1, 100, 1 d. 40 400 4
main() { int i=0; for(;i++;printf("%d",i)) ; printf("%d",i); }
program to find magic aquare using array
Predict the Output: int main() { int *p=(int *)2000; scanf("%d",2000); printf("%d",*p); return 0; } if input is 20 ,what will be print
1) int i=5; j=i++ + i++ + i++; printf("%d",j);This code gives the answer 15.But if we replace the value of the j then anser is different?why? 2)int i=5; printf("%d",i++ + i++ + i++); this givs 18.
main() { int i=5,j=10; i=i&=j&&10; printf("%d %d",i,j); }
Ramesh’s basic salary is input through the keyboard. His dearness allowance is 40% of basic salary, and house rent allowance is 20% of basic salary. Write a program to calculate his gross salary.