program to find the roots of a quadratic equation
Answer Posted / lady k
#include<stdio.h>
#include<conio.h>
#include<math.h>
#include<stdlib.h>
int main ()
{
/*Main: Solve the quadratic equation*/
float r, a, b, c, x1, x2, d;
printf ("Enter the value of a: ");
scanf ("%f", &a);
printf ("\nEnter the value of b: ");
scanf ("%f", &b);
printf ("\nEnter the value of c: ");
scanf ("%f", &c);
printf("\n");
d= b*b-4*a*c;
r= sqrt(d);
x1= (-b + r)/(2*a);
x2=(-b- r)/(2*a);
if (d>0)
{
printf ("The real roots of the equation are %f",
x1);
printf (" and %f", x2);
}
else if (x1==x2)
{
x1= (-b+r)/(2*a);
printf ("x1 and x2 are equal roots %f", x1);
}
else if (a<0)
{
x1= (-b + r)/(2*a);
x2=(-b- r)/(2*a);
printf ("The roots of the equation are %f", x1);
printf (" and %f", x2);
}
else
printf ("The roots of the equation are
complex");
getch ();
return 0;
}
Is This Answer Correct ? | 12 Yes | 6 No |
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