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2 batsmen each on 94. 7 runs to win inlast 3 balls. Both
make unbeaten 100 . how?
- 24 Answers
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Answer / navjot siddhu
Are Bhai Itna Matha pachhi nahi karne ka , sidha pahle 2
ball par 2 six maro 1 ka 100 ho gaya, baad me scorer ke sar
pe maro 2 ka bhi 100 ho jayega.
| Is This Answer Correct ? | 5 Yes | 23 No |
Answer / karthik
hey its very nice ya
we have to think out of line in this question
Batsman1: have to hit 4 runs (remaining 3)
Batsman1: Have to hit for 3 run after getting 2 runs he would
make himself run out at bowler end(1 rum remaining)
Batsman2: Have to hit a Six at last ball
now both are 100 and they will win
how is it
| Is This Answer Correct ? | 21 Yes | 49 No |
Answer / krishna
All the above answers are worng guys!!!!!!!Batsman 1 will
hit 6 then the next ball catch but cross over then another
batsman 6 so both gets 100 very simple!!!!!!
| Is This Answer Correct ? | 2 Yes | 33 No |
Answer / karthik
batsmen 1 have to hit a 6 at first ball
then he must take a single to make other batsmen on the hit
field
now the second batsmen have to hit the six at last ball
by doing so, both will get 100 in the matches
| Is This Answer Correct ? | 5 Yes | 98 No |
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