Answer / aza

WHAT 130 STANDS FOR IN ANSWER NUMBER 2??

Answer / bhushan

UPS / Invertor Battery Backup Time =
----------------------------------


Batt Voltage X No.of (Batteries) X Single Battery Ah /
Total Load (Watts) = No.Hours Backup


Example :- 12v X 20(Batteries) X 200Ah (Single Battery)
/ 6000 Watts = No.Hours Backup


48000 / 6000 Watts = 8 Hours Backup
BHUSHAN

Answer / cree led street light in pakis

thanks for the useful information you people share

Answer / ms

su-kam inverter company saying in a restive load backup time will be battery ah*battery v*80%/total load.(20% is battery

Answer / mana

UPS Bachup time=(Battery AH*No.ofbattery/UPS capacity in
kva*130)*60=mins

Answer / chesda

T = (N.Q.eff.PF.V)/Load

T : Backup time [h]
N : Number of batteries [Nos]
Q : Batteries charge [AH]
eff : Inverter efficiency [%]
PF : Load power factor
V : Batteries voltage [V]
Load : Connected load [W]

Answer / tapas

UPS Battery Backup time= (No. of battery X Volt per battery X Battery AH)/ Load in VA

(No. of battery X Volt per battery X Battery AH)
Backup = ------------------------------------------------
time Load in VA

Note: KW should be converted to VA before applying the formula

Answer / basanta das

Ups Standard Bacup Time = (Battery Volt X Each Battery Ah X No. Of Batteries) / load in VA
For example: Volt 12 x AH 26 x Total batteries 16 = 4992
Now divide the above with required load (1 KVA) =1000VA
So result is 4992/1000 = 4.992 hours
Means your UPS will run for 4.992 hours in standard calculation method, but in actual there will be a UPS energy waste or dissipation, let your UPS efficiency is 80% then you will get actual time
4.992 x 0.80 = 3.9936 hours i.e approx. 4 hours of backup time for 1KVA load if you have 12volt, 26AH battery of 16 nos.

Answer / sudarshan

i hv 600kva ups
how many batterys required
with formule

Answer / akshay kumar

UPS BACKUP TIME=CONNECTED LOAD/(BATTERY VOLTAGE*NO. OF
BATTERY)
SUPPOSE CONNECTED LOAD = 1KVA,BATTERY VOLTAGE=12,NO OF
BATTERY=2 THEN
BACKUP TIME =1000(1KVA)/12*2
=1000/24=41.67 AH
(IT MEANS BATTERY DISCHARGE CURRENT =41.67 AH IN ONE HR.)

IF YOUR BATTERY CAPACITY IS 150 AH THEN
BACKUP TIME=150/41.67
=3.35 HRS (APPROX)

We have a 33/11kv switchyard having 12.5 MVA power transformer. We export & import power through this transformer. When we export power, the PF will be depend on GRID PF & when we import power the PF will be depend on our load PF. but the problem is that,when neither we export nor import but our 33KV vCB is in close position,our meter read the power factor 0.14 to 0.25 at that moment. So how can be we improve the power factor at that moment.

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