if a number is choosen between 100 and 999 includeing these
numberrs what is the provbabilty that the number selected
does not contain a 7 is
Answers were Sorted based on User's Feedback
Answer / naveen
no. of occurrences of 7 in
100-199 =
107,117,127,137,147,157,167,170,171,172,173,174,175,176,177,178,
179,187,197 =19
lly for
200-299=19
300-399=19
400-499=19
500-599=19
600-699=19
now
700-799=100
800-899=19
900-999=19
total =8*19+100=152+100=252
probability = 1-(252/899)=0.71
Is This Answer Correct ? | 5 Yes | 8 No |
Answer / ankit kumar
Total numbers between 100 & 999 = 900 (including both)
Possible combinations for conaiting 7:
7** = 1x9x9=81
*7* = 8x1x9=72
**7 = 72
77* = 9
7*7 = 9
*77 = 8
777 = 1
Total = 252
Therefore probability = 252/900 or 7/25
Is This Answer Correct ? | 0 Yes | 3 No |
Answer / fayaz
no.of numbers having 7 between 100 & 999 (inclusive)=280(by combination)
total numbers between 100& 999(inclusive)=900
probability of having 7 in the chosen no.=280/900=.311
thus probability of not having 7 in chosen no.=1-.311=0.688
Is This Answer Correct ? | 1 Yes | 4 No |
Answer / sandhya
let take xyz as number that can qualify our condition...
x can have capable of arranging in 8 ways bcoz 0 and 7 are
omitted..
y can can have capable of arranging in 9 ways bcoz 7 is
omitted...
z also same as y.
so totally we can get 8*9*9 ways and total numbers exist in
b/w 100 and 999 is 899
so the answer is 8*9*9/899
Is This Answer Correct ? | 3 Yes | 9 No |
Answer / paresh
Total number between 100 and 900 are 888
from 700-799 total numbers are 100
100-199 numbers containing 7 are 107,117,...170-179,187,197
are 19
now total numbers from 100-900 except 700-799 are 19*7 = 133
so finally numbers containg 7 are = 133+100 = 233
Probability that number do not have 7 is = 1-233/888 = .737
Is This Answer Correct ? | 3 Yes | 11 No |
Answer / vicky
total numbers between 100 and 999 is 888.
between 100 and 2oo,ther are 11 numbers with 7.
similar case for all the intervals.but from 700 to
8oo,there are 100 numbers with 7.
so,totally,
7*11+100=177
therefore,the probability of not having 7 is
1-(177/888)=0.8006
Is This Answer Correct ? | 1 Yes | 14 No |
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