if a number is choosen between 100 and 999 includeing these
numberrs what is the provbabilty that the number selected
does not contain a 7 is
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Answer / satheshramasamy
no 0f 7's in 100 to 200 is
107,117,127,137,147,157,167,170,171,172,173,174,175,176,177,
178,179,187,197.
so totally 20 7's in 100-200.
so totally we have (20*9 +1) sevens b/w 100-999.totalling
181.
therefore prob is 181/((999-100)+2)=181/901=0.2009
| Is This Answer Correct ? | 2 Yes | 16 No |
Answer / subbu
nos with 7 from 100 to 200 = 107,117,127,....197 and 170.
so 11.
like wise from 200 to 300 it is 11.
therefore...9 * 11 = 88.
total nos=900.
prob without 7's =1-99/900= 0.89
| Is This Answer Correct ? | 3 Yes | 21 No |
Answer / sabarish
nos with 7 from 100 to 200 = 107,117,127,....197 and 170.
so 11.
like wise from 200 to 300 it is 11.
therefore...8 * 11 = 88.
total nos=899.
prob without 7's =1-88/899= 0.902 approx
| Is This Answer Correct ? | 6 Yes | 34 No |
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