When a square wave is applied to primary of a transformer
then what will be output wave form of secondary ?
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Answer / fabio corsi
A Fourier analysis may be applied only if a transformer is
linear, which is rarely the case; furthermore, even in a
linear transformer, the dispersed flux has to be accounted,
i.e. flux produced by the primary current which is not
chained with the secondary coil and viceversa.
In a linear transformer without dispersed flux and with zero
resistance of the coils, the waveform of the secondary
voltage is the same as that of the primary voltage, since
u1=N1*d(flux)/dt and u2=N2*d(flux/dt), the flux being the
same, i.e. u1/u2=N1/N2 no matter the waveform (provided it
can be integrated, which is also the case of a square wave).
This is no longer the case with dispersed flux, and/or with
coil resistance, and/or with non-linear core (e.g. iron), in
which case all depends on the involved parameters
(inductance of dispersed flux, hysteresis cycle of the core,
resistance of the coils and consequent time constants w.r.t
the working frequencies).
In a nutshell: "ideal" transformer(never the case actually)
==> square wave; non-ideal transformer ==> non-square
waveforms, the more distorted the less the transformer may
be approximated as ideal, possibly even spikes.
| Is This Answer Correct ? | 30 Yes | 4 No |
Answer / devang
when flux change the voltage induced on secondary side so
we can not use the transformer as dc value step-up-down so
for constant value of square the output zero but the
transformer has the storage energy so the enery decrease
with time constant for high value of time constant the
square value possible but less value of time constant the
squre value not possible
| Is This Answer Correct ? | 21 Yes | 3 No |
Answer / vinodkumar
transformer acts as a differentiator. so when you apply a square waveform after some time t1 or so core gets saturated results in constant flux so rate of change of flux is zero so output voltage zero.so if we summerize the above points output waveform would a spike
| Is This Answer Correct ? | 17 Yes | 0 No |
Answer / lotec
the output on the secondary will be altinating positive and
negative spikes corresponding to the rapid rise and fall
times of the square wave on the primary. you will get one
positive and one negative spike corresponding to the outside
edges of the square.
| Is This Answer Correct ? | 10 Yes | 1 No |
Answer / maruguthi bharathkumar
can u please give me matlab simulation to this question..
| Is This Answer Correct ? | 0 Yes | 0 No |
Distorted square wave will the voltage on the secondary
| Is This Answer Correct ? | 6 Yes | 7 No |
Answer / praveen
normally transformer coil is like an inductor l=ldi/dt , so
rate of change of current important in square wave rate of
change is happened means the transformer changes it value
| Is This Answer Correct ? | 6 Yes | 11 No |
Answer / shekhar
transformer doesn't change the waveshape it just changes its
value and also frequency remains same so obviously output
would be square wave with changed value depends on
transformation ratio
| Is This Answer Correct ? | 42 Yes | 48 No |
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