how to calculate the slowness and fastness of energy meter if we have different kw load for example (0.746 kw and meter rev constant 400 and we calculate the 2 rev in 30 sec) please explain the formula thanks
Meter rev constant means rev/ kwh ? Then one rotation =60x60/400 or 9kws . 2 rotations = 18kws.Time taken is 30s. Then the av load is 18/ 30 or 0.6 kw
| Is This Answer Correct ? | 2 Yes | 2 No |
I am getting above 60 V as open delta voltage against single phase unit ICT at tertiary delta formed and ICT getting trippped on NDR. ICT tested and found in order. PTs provided on tertiary are tested and in order. what may be the reason?
i want to ask that as everybody knows that in star connection on star point is called neutral. my question is that why on that poin called neutral. what is the reason behind it. what is the logic behind it. i heared somewhere that on this point all phases current become zero thats why. if this answer is right then prove why on that point is current become zero. if this answer is not right then tell me the right answer. post ur answer here or on my mail address. m.ikram786@yahoo.com m.ikram555@gmail.com. thanks.
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