main()
{
int *ptr=(int*)malloc(sizeof(int));
*ptr=4;
printf("%d",(*ptr)+++*ptr++);
}
Answers were Sorted based on User's Feedback
Answer / john lee
main()
{
int *ptr=(int*)malloc(sizeof(int));
*ptr=4;
printf("%d",(*ptr)++ + (*ptr)++);
}
Like above, code should be revised as allocated memory space just has 2(16bit machine) or 4 byte(32bit machine) to save '4'.
If not, the orginal code, printf("%d",(*ptr)++ + *ptr++);
In my guess, ptr++ will be first, and then *ptr would be next.
If so, ptr++ will point to a memory address unintended(an address +2 or +4 added). And then *ptr will have a value like 0 or else.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / vinod
Answer = 8
Explanation:
*ptr=4;
printf("%d",(*ptr)+++*ptr++);
The above statement can be interpreted as (*ptr)++ + *ptr++
(*ptr)++ - Post increment the Value pointer by ptr i.3. 4
*ptr++ - Return the value of ptr and increment the position of ptr i.e. 4
So (*ptr)++ + *ptr++ => 4 + 4 => 8
| Is This Answer Correct ? | 1 Yes | 2 No |
How can i find first 5 natural Numbers without using any loop in c language????????
main() { int i=-1; -i; printf("i = %d, -i = %d \n",i,-i); }
main() { main(); }
main() { int i=400,j=300; printf("%d..%d"); }
main() { char *a = "Hello "; char *b = "World"; clrscr(); printf("%s", strcat(a,b)); } a. Hello b. Hello World c. HelloWorld d. None of the above
main() { printf("%d, %d", sizeof('c'), sizeof(100)); } a. 2, 2 b. 2, 100 c. 4, 100 d. 4, 4
18 Answers HCL, IBM, Infosys, LG Soft, Satyam,
#include<stdio.h> int main() { int x=2,y; y=++x*x++*++x; printf("%d",y); } Output for this program is 64. can you explain how this output is come??
can u give me the c codings for converting a string into the hexa decimal form......
#include<stdio.h> int main() { int a=3,post,pre; post= a++ * a++ * a++; a=3; pre= ++a * ++a * ++a; printf("post=%d pre=%d",post,pre); return 0; }
main() { register int a=2; printf("Address of a = %d",&a); printf("Value of a = %d",a); }
write a program to Insert in a sorted list
Write a procedure to implement highlight as a blinking operation